Question

我正在使用ElementTree处理XML文件，每个文件大约有5000个“资产”节点

<asset id="83">
    <name/>
    <tag>0</tag>
    <vin>3AKJGLBG6GSGZ6917</vin>
    <fleet>131283</fleet>
    <type id="0">Standard</type>
    <subtype/>
    <exsid/>
    <mileage>0</mileage>
    <location>B106</location>
    <mileoffset>0</mileoffset>
    <enginehouroffset>0</enginehouroffset>
    <radioaddress/>
    <mfg/>
    <inservice>04 Apr 2017</inservice>
    <inspdate/>
    <status>1</status>
    <opstatus timestamp="1491335031">unknown</opstatus>
    <gps>567T646576</gps>
    <homeloi/>
</asset>

我需要
资产节点上id属性的值
vin节点的文本
gps节点的文字

如何直接读取“ vin”和“ gps”子节点的文本，而不必遍历所有子节点？

for asset_xml in root.findall("./assetlist/asset"):
    print(asset_xml.attrib['id'])
    for asset_xml_children in asset_xml:
        if (asset_xml_children.tag == 'vin'):
            print(str(asset_xml_children.text))
        if (asset_xml_children.tag == 'gps'):
            print(str(asset_xml_children.text))

Answer 1

您可以相对于每个asset元素执行XPath来直接获取vin和gps而不循环：

for asset_xml in root.findall("./assetlist/asset"):
    print(asset_xml.attrib['id'])

    vin = asset_xml.find("vin")
    print(str(vin.text))

    gps = asset_xml.find("gps")
    print(str(gps.text))

如何阅读ElementTree中特定子节点的文本？

1 个答案: