Question

我有一个日期时间数组-我需要一个对象，其中的键将日期分组，值应该是该日期的时间数组。来源：

[
    "2019-02-18T11:30:00+01:00",
    "2019-02-18T13:00:00+01:00",
    "2019-02-19T13:30:00+01:00",
    "2019-02-19T16:30:00+01:00",
    "2019-02-20T17:00:00+01:00",
    "2019-02-20T17:30:00+01:00",
    "2019-02-20T18:00:00+01:00"
]

我需要这个：

{
    '2019-02-18': [
        '11:30:00+01:00',
        '13:00:00+01:00'
    ],
    '2019-02-19': [
        '13:30:00+01:00',
        '16:30:00+01:00'
    ],
    ...
}

一种解决方案是循环数组，剥离前10个字符并与其他日期时间匹配-tbh不太好。

Answer 1

您可以将reduce与split一起使用

let data = ["2019-02-18T11:30:00+01:00","2019-02-18T13:00:00+01:00","2019-02-19T13:30:00+01:00","2019-02-19T16:30:00+01:00","2019-02-20T17:00:00+01:00","2019-02-20T17:30:00+01:00","2019-02-20T18:00:00+01:00"]

let op = data.reduce(( op, inp ) => {
  let [key,value] = inp.split('T')
  if( op[key] ){
    op[key].push(value)
  } else {
    op[key] = [value]
  }
  return op
},{})

console.log(op)

Answer 2

一种选择是将Array.reduce()与String.match()结合使用

const input = [
    "2019-02-18T11:30:00+01:00",
    "2019-02-18T13:00:00+01:00",
    "2019-02-19T13:30:00+01:00",
    "2019-02-19T16:30:00+01:00",
    "2019-02-20T17:00:00+01:00",
    "2019-02-20T17:30:00+01:00",
    "2019-02-20T18:00:00+01:00"
];

let res = input.reduce((acc, date) =>
{
    let [m, d, t] = date.match(/(.+)T(.+)/);
    acc[d] = [...(acc[d] || []), t];
    return acc;
}, {});

console.log(res);

从分组日期时间创建对象

2 个答案: