Question

我有以下数据

Base          End
RMSA          Item 1
RMSA          Item 2
RMSA          Item 3
RMSB          Item 1
RMSB          Item 2
RMSC          Item 4

我想将其转换为以下格式

    Key           Products
    RMSA;RMSB     Item 1, Item 2
    RMSA          Item 3
    RMSC          Item 4

基本上，那些结果相似的应该归为1行。但是，由于要在两列上进行分组，因此我似乎无法使用listagg等使它正常工作。

是否可以通过直接Oracle查询来执行此操作？

Answer 1

您可以将listagg()窗口分析函数两次用作

with t1( Base, End ) as
( 
 select 'RMSA','Item 1' from dual union all
 select 'RMSA','Item 2' from dual union all 
 select 'RMSA','Item 3' from dual union all
 select 'RMSB','Item 1' from dual union all
 select 'RMSB','Item 2' from dual union all
 select 'RMSC','Item 4' from dual 
),
   t2 as
(   
select 
       listagg(base,';') within group (order by end) 
       as key,
          end   
  from t1
 group by end 
)
select key, 
       listagg(end,',') within group (order by end) 
       as Products
  from t2  
 group by key
 order by products;

Key           Products
---------     --------------
RMSA;RMSB     Item 1, Item 2
RMSA          Item 3
RMSC          Item 4

Demo

Answer 2

下面是一种方法-

WITH base 
     AS (SELECT 'RMSA'   AS base, 
                'Item 1' AS end1 
         FROM   dual 
         UNION 
         SELECT 'RMSA'   AS base, 
                'Item 2' AS end1 
         FROM   dual 
         UNION 
         SELECT 'RMSA'   AS base, 
                'Item 3' AS end1 
         FROM   dual 
         UNION 
         SELECT 'RMSB'   AS base, 
                'Item 1' AS end1 
         FROM   dual 
         UNION 
         SELECT 'RMSB'   AS base, 
                'Item 2' AS end1 
         FROM   dual 
         UNION 
         SELECT 'RMSC'   AS base, 
                'Item 4' AS end1 
         FROM   dual), 
     t11 
     AS (SELECT t1.base base1, 
                t1.end1 AS end11, 
                t2.base base2, 
                t2.end1 AS end12 
         FROM   base t1 
                inner join base t2 
                        ON t1.end1 = t2.end1 
         WHERE  t1.base > t2.base) SELECT 
Concat(Concat(t11.base1, ';'), t11.base1), 
       Listagg(t11.end11, ',') 
         within GROUP (ORDER BY t11.end11) 
FROM   t11 
GROUP  BY Concat(Concat(t11.base1, ';'), t11.base1) 
--above query will get you results where you have similar results 
UNION 
SELECT t1.base, 
       t1.end1 
FROM   base t1 
       left outer join t11 
                    ON t1.base = t11.base1 
                       AND t1.end1 = t11.end11 
       left outer join t11 t12 
                    ON t1.base = t12.base2 
                       AND t1.end1 = t12.end11 
WHERE  t11.base1 IS NULL 
       AND t12.base2 IS NULL;

希望这会有所帮助

转置和汇总Oracle列数据

2 个答案: