Question

我有一个数据数组（数组A的所有值都是string）：这是数据输入（http://pastebin.com/H8wv9aJU）

 $A = Array
  0=>(
      [0] => "03"//main
      [1] => "04"//sub
      [2] => "05"
      [3] => "07"

  [4] => "03" //main
    [5] => "04"//sub
      [6] => "05"
      [7] => "06"
      [8] => "07"
    [9] => "04"//sub
      [10] => "05"
      [11] => "06"
      [12] => "07"
    [13] => "04"//sub
      [14] => "05"
      [15] => "07"

  [16] => "03" //main 
    [17] => "04"//sub
      [18] => "05"
      [19] => "06"
      [20] => "07"
    [21] => "04"//sub
      [22] => "05"
      [23] => "06"
      [24] => "07"
    [25] => "04"//sub
      [26] => "05"
      [27] => "07"
  );

预期结果（04和07之间的某些元素可能会丢失）：

Array
(
[0] => Array // "03"
    (
    [0] => "030405  07" //because missing 06 see here 2 space
    )

[1] => Array // "03"
    (
    [0] => "0304050607" //concatenate it all together
    [1] => "0304050607"//concatenate it all together
    [2] => "030405  07"//because missing 06see here 2 space
    )

[2] => Array // "03"
    (
    [0] => "0304050607" //concatenate it all together
    [1] => "0304050607" //concatenate it all together
    [2] => "030405  07"//because missing 06, see here 2 space
    )

)

我尝试过：

$r = -1;
$organized_array = array();//array expected result. 
foreach($A as $key=>$rec) {
    if(substr($rec,0,2) == "03") {
        // CHANGE 1
      $save = $rec;// saved "03" yo put in child too.
      ++$r;//inc parent => $r became 0
        $j = 0; // child 
        $organized_array[$r][$j] = str_replace(array("\r", "\n"), "",$rec);
      }
         else {
          //I STUCKED HERE FOR GETTING THE EXPECTED RESULT
        if (($j % 3) > 0) $rec =  str_replace(array("\r", "\n"), "",$rec);
        // CHANGE 2
        else if ($j && $j % 3 == 0) $rec = str_replace(array("\r", "\n"), "",$save.$rec);
        $organized_array[$r][floor($j / 3)] .= str_replace(array("\r", "\n"), "", $rec);
        ++$j;//increment child
    }
}

任何人我有什么不对吗？

Answer 1

我想这是解决问题的方法......

如果您有这样的数组

$A = array("03", "04", "05", "07", "03", "04", "05", "06", "07", "04", "05",
"06", "07", "04", "05", "07", "03", "04", "05", "06", "07", "04", "05", "06",
"07", "04", "05", "07");

...和预期的输出如下：

array(3) {
  [0]=>
  array(1) {
    [0]=>
    string(10) "030405  07"
  }
  [1]=>
  array(3) {
    [0]=>
    string(10) "0304050607"
    [1]=>
    string(10) "0304050607"
    [2]=>
    string(10) "030405  07"
  }
  [2]=>
  array(3) {
    [0]=>
    string(10) "0304050607"
    [1]=>
    string(10) "0304050607"
    [2]=>
    string(10) "030405  07"
  }
}

试试这个代码！

$r = -1; $r2 = 0; $last_rec = 2;
$organized_array = array();
foreach ($A as $key => $rec) {
  if ($rec == "03") {
    // parent
    if ($r >= 0) $organized_array[$r][$r2] = str_pad($organized_array[$r][$r2], 10, '  ');
    $r++;
    $r2 = 0;
    $organized_array[$r][$r2] = "03";
    }
  else {
    // children
    $this_rec = $rec * 1;
    if ($this_rec < $last_rec) {
      $organized_array[$r][$r2] = str_pad($organized_array[$r][$r2], 10, '  ');
      $r2++;
      $organized_array[$r][$r2] = "03";
      }
    if ($this_rec > ($last_rec + 1)) {
      $ec = $this_rec - $last_rec - 1;
      $organized_array[$r][$r2] .= str_repeat("  ", $ec);
      }
    $organized_array[$r][$r2] .= $rec;
    }
  $last_rec = $rec * 1;
  }

var_dump($organized_array);

希望有所帮助！

将数组元素组合成2个暗淡的数组？

1 个答案: