Question

我正在使用Codeigniter，并尝试使用数据库中的用户名上传图像名称。在我的视图文件中，有两个字段，一个是输入字段，第二个是文件类型输入字段。但是，当我尝试将第一个输入字段的值从一个函数传递给另一个函数时，它会显示空白。这是我的代码...

控制器

class img_upload extends CI_Controller
{
    public function index()
    {
        $data['title'] = 'Image Upload & Display';
        $this->load->view('img_upload_view',$data);     
    }
    public function check_img()
    {
        $this->load->library('form_validation');

        $this->form_validation->set_rules('name', 'Name', 'required');
        $this->form_validation->set_rules('userfile', 'Userfile', 'callback_image_validation');

        if($this->form_validation->run() == false)
        {
            $this->index();
        }
        else
        {
            $data['name'] = $this->input->post('name');
            $this->image_validation($data['name']);
        }
    }
    public function image_validation($data)
    {
        $name = $data['name'];
        $config['upload_path']  = './upload/';
        $config['allowed_types'] = 'gif|jpg|png';

        $this->load->library('upload', $config);

        if ( ! $this->upload->do_upload('userfile'))
        {
            $error =  $this->upload->display_errors();
            $this->form_validation->set_message('image_validation', $error);
            return false;
        }
        else
        {
            $data = $this->upload->data();
            $img = $data['file_name'];

            $data = array(
                'name' => $name,
                'img_name' => $img
            );

            $this->load->model('img_model');
            $this->img_model->Insert_Data($data);

            $this->session->set_flashdata('success', "Data Inserted Successfully!");

            return true;
        }
    }
}

模型

class img_model extends CI_Model
{
    public function Insert_Data($data)
    {
        $this->db->insert('image', $data);
    }
}

视图

<!DOCTYPE html>
<html>
<body>
    <div class="container">
        <div class="row justify-content-md-center">
            <div class="col-md-8">
                <br>
                <div class="card">
                    <div class="card-body">
                        <h5 class="card-title"><h2><?php echo $title; ?></h2></h5>
                        <p class="card-text">
                        <?php if($this->session->flashdata('success') == '')
                        {
                        echo $this->session->flashdata('success');
                        }
                        ?>
                        <?php echo form_open_multipart('img_upload/check_img'); ?>
                        <div class="form-group">
                        <label for="exampleInputName">Name</label>
                        <input type="text" class="form-control" placeholder="Enter username" name="name">
                        <span><?php echo form_error('name');?></span>
                        </div>  
                        <div class="form-group">
                        <label for="exampleInputUpload">Upload</label>
                        <input type="file" class="form-control" name="userfile">
                        <span><?php echo form_error('userfile');?></span>
                        </div>
                        <button type="submit" class="btn btn-primary">Submit</button>
                        </form>
                        <br>
                        <div class="img-reponsive">
                        <!-- <img src="<?php #echo 'upload/'.$images->img_name; ?>" height="150" width="150"> -->  
                        </div>
                        </p>
                    </div>
                </div>

            </div>
        </div>

    </div>
</body>

</html>

错误

   A Database Error Occurred
   Error Number: 1048

   Column 'name' cannot be null

   INSERT INTO `image` (`name`, `img_name`) VALUES (NULL, 'c4.jpg')

   Filename: C:/xampp/htdocs/image_upload/system/database/DB_driver.php

   Line Number: 691

Answer 1

您无法在控制器中将数据作为数组传递更改

    $data['name'] = $this->input->post('name');
    $this->image_validation($data['name']);

至

    $name = $this->input->post('name');
    $this->image_validation($name);

尝试一下

public function check_img(){

$this->load->library('form_validation');
$this->form_validation->set_rules('name', 'Name', 'required');
$this->form_validation->set_rules('userfile', 'Userfile', 'callback_image_validation');

if($this->form_validation->run() == false)
{
    $this->index();
}
else
{
    $data['name'] = $this->input->post('name');

    $config['upload_path'] = './upload/';
    $config['allowed_types']        = 'jpeg|jpg|png|gif';

    $this->load->library('upload', $config);
    $this->upload->initialize($config);
    if ( ! $this->upload->do_upload('image'))
    {
        $error = array('error' => $this->upload->display_errors());
        echo json_encode($error);
    }
    else{ 
        $upload_data = $this->upload->data();
        $data['img_name'] = $upload_data['file_name'];

        $this->load->model('img_model');
        $this->img_model->Insert_Data($data);

        $this->session->set_flashdata('success', "Data Inserted Successfully!");
        return true;
    }
}
}

Answer 2

无需转到另一个函数image_validation（）。您可以在以下相同的else子句中插入数据。

public function check_img()
{
    $this->load->library('form_validation');

    $this->form_validation->set_rules('name', 'Name', 'required');

    if($this->form_validation->run() == false)
    {
        $this->index();
    }
    else
    {
        //$data['name'] = $this->input->post('name');
        //$this->image_validation($data['name']);

        $name = $this->input->post('name');

        if( $_FILES['userfile']['name']!='' && $_FILES['userfile']['size'] > 0 )
        {
            //NOTE :- To give uploaded image your Input field name, pass the $name variable to $config['file_name'] name.

            $config['file_name'] = $name;
            $config['upload_path']  = './upload/';
            $config['allowed_types'] = 'gif|jpg|png';

            //load library
            $this->load->library('upload');
            $this->upload->initialize($config);

            if( $this->upload->do_upload('userfile') )
            {
                $data = $this->upload->data();
                $img = $data['file_name'];

                $data = array(
                    'name' => $name,
                    'img_name' => $img
                );

                $this->load->model('img_model');
                $this->img_model->Insert_Data($data);

                $this->session->set_flashdata('success', "Data Inserted Successfully!");
                return true;
            }
            else
            {
                $error =  $this->upload->display_errors();
                $this->form_validation->set_message('image_validation', $error);
                return false;
            }
        }
        else
        {
            //show error to select Image.
        }
    }
}

使用输入名称字段上传图像

2 个答案: