Question

我在数据库中有一个项目列表，我想在表中呈现它，并将为每个项目添加输入type = file以为每个项目上传文件在句柄上单击，我想发送项目名称以处理函数，但我做不到，为了更清楚，我想每次单击时都将value item.documentname发送到file1MadChangedHandler函数。

   {this.props.Organizations.listDocs 
    ? 
    <div>
       { this.props.Organizations.listDocs.map(function (item, index) {
          return(
                <tr key={item.documentName}>
                    {item.documentName}
                        <td>
                        <td>
                            <input component="input"
                                type="file"
                                id="{item.documentName}"
                                onChange={(event,item)=> { 
                                    this.file1MadChangedHandler(event,item) }}
                                // onChange={this.file1MadChangedHandler}
                                ref={fileInput => ref.fileInput = fileInput}
                                style={{ display: "None" }}
                            />
                            <button onClick={(item) => this.fileInput.click(item.documentName)}>Pick File</button>             
                        </td>
                </tr>
            )

        })
                }
    </div> 
    : 
    ""
}

Answer 1

fileHandler = (event) => {
  if(event.target.value !== ""){
    event.preventDefault();
    this.form.validateFields(event.target.name);

    const fileObject = event.target.id;  
    const name = event.target.files[0].name;
    const size = ((event.target.files[0].size)/1000000).toFixed(2);
    let img = [...this.state.img];

    img.push({inptid: fileObject,
      name: name,
      size: size});

    const fetchImage = img.map(e => e['inptid'])
    .map((e, i, final) => final.lastIndexOf(e) === i && i)
    .filter(e => img[e]).map(e => img[e]);

    this.setState({ img: fetchImage});

  }else{
    return false;
  }
}

请注意，根据情况，我们的渲染部分和表单会通过循环动态生成，

<input
  type="file"
  className="form-control none"
  ref={formfields.title}
  name={formfields.title}
  id={formfields._id}
  key={formfields._id}
  index={formindex}
  onChange={this.fileHandler}
  required
/>

{
  img.filter(data => data.inptid === formfields._id)
  .map((data,index) =>{
    return(
      (data.inptid === formfields._id)
      ?
      <p>{data.name}   - <i><b>{data.size} MB </b></i></p>
      :
      ''
    )
  }) 
}

Answer 2

使用您的repl.it/repls/MutedFunnyBlog代码的输入。

要获取上传项目的文件名，您需要对数据进行如下更改：

AsyncStorage.clear()

然后渲染每一行，如下所示：

data: [
      { id: 1, name: "Copy of Applicant's Identification Card / Passport", "file": "" },
      { id: 2, name: "Copy of Business Registration Certificate (eg. SSM)", "file": "" },
      { id: 3, name: "Copy of Business Registration File 1", "file": "" },
      { id: 4, name: "Copy of Business Registration File 2", "file": "" }
    ]  //added file

并在handleChange事件中

   data.map((item, index) => {
    return(
      <tr key={`${this.state.inputkey}${item.id}`}>
        <td width="100">{item.id}</td>
        <td width="300">{item.name}</td>
        <td width="200">{item.file}</td> /* your third column */
        <td>
        <input 
          key={this.state.inputkey} /*unique key */
          type="file" 
          id={item.id} /*unique id cus every row should have unique input file type*/
          className="inputfile"
          onInput ={(e) => this.handleChange(e,item.id)} 
          data-name={item.id} />
        <label htmlFor ={item.id} > /* unique id for file upload*/
          <figure>
            <svg xmlns="http://www.w3.org/2000/svg" width="20" height="17" viewBox="0 0 20 17"><path d="M10 0l-5.2 4.9h3.3v5.1h3.8v-5.1h3.3l-5.2-4.9zm9.3 11.5l-3.2-2.1h-2l3.4 2.6h-3.5c-.1 0-.2.1-.2.1l-.8 2.3h-6l-.8-2.2c-.1-.1-.1-.2-.2-.2h-3.6l3.4-2.6h-2l-3.2 2.1c-.4.3-.7 1-.6 1.5l.6 3.1c.1.5.7.9 1.2.9h16.3c.6 0 1.1-.4 1.3-.9l.6-3.1c.1-.5-.2-1.2-.7-1.5z"/>
            </svg>
          </figure> 
        </label>           
        </td>
      </tr>
    );
});

Demo，希望它可以解决您的问题。

reactjs形式的多个文件上传器

2 个答案: