美好的一天,我只想问一下,为什么我上次使用它时却无法从这段代码中获取图像。
这是功能
/*ADDING SECTION*/
public function AddHomeImages($images){
try{
$stmt = $this->db->prepare("INSERT INTO home(image) VALUES(:images)");
$stmt->bindParam(":images", $images);
$stmt->execute();
return $stmt;
}catch(PDOException $ex){
echo $ex->getMessage();
}
}
这就是我将其上传到文件夹的方式
<?php
/*---------DEVELOPMENT-----------*/
require_once '/database/database.php';
if(isset($_POST['btn-home-submit'])){
// $file = $_FILES['file'];
if(!empty($_FILES['file']['tmp_name'])){
move_uploaded_file($_FILES['file']['tmp_name'],"images/sliding_images/" . $_FILES['file']['name']);
}else{
//nothing
}
$location = $_FILES['file']['name'];
if($user->AddHomeImages($location)){
header("Location: admin-index.php?uploadedsuccessfully");
}
}
?>
现在它可以成功地将文件上传并移动到该文件夹以及数据库中了,我现在想使用此代码来显示它
<?php
require_once '/database/database.php';
$stmt = $db_con->prepare("SELECT * FROM home");
$stmt->execute();
<div class="owl-carousel owl-carousel-fullwidth">
while($userRow=$stmt->fetch(PDO::FETCH_ASSOC)){
echo "<div class='item'";
echo "<img src='images/sliding_images/" .$userRow['image']. "' alt='UTEC PHOTO'>";
echo "<div class='slider-copy'";
echo "<h2>Architecture " .$userRow['id']. "</h2>";
echo "</div>";
echo "</div>";
}
</div>
?>
但是它只能得到$userRow['id']
而不是图像。这是屏幕截图
控制台上实际上没有错误。有人帮我。
答案 0 :(得分:0)
Replace part of code.
echo "<div class='item'";
With below code(missing >).
echo "<div class='item'>";