Question

我在UserDAO和hibernate中使用它

@Resource(name="sessionFactory");
public SessionFactory sessionFactory;

由于某些原因，我无法从我的userDAO中链接来自2个不同类的spring bean。

上述代码的另一种替代方法是什么意思

SessionFactory sessionFactory = new Sessionfactory()

没关系

的web.xml

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5">
  <display-name>testing</display-name>


  <filter>
            <filter-name>springSecurityFilterChain</filter-name>
            <filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
    </filter>

    <filter-mapping>
            <filter-name>springSecurityFilterChain</filter-name>
            <url-pattern>/*</url-pattern>
    </filter-mapping>

    <context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>
        /WEB-INF/spring-security.xml

        </param-value>
    </context-param>




  <servlet>
        <servlet-name>dispatcher</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <load-on-startup>1</load-on-startup>
    </servlet>
    <servlet-mapping>
        <servlet-name>dispatcher</servlet-name>
        <url-pattern>/krams/*</url-pattern>
    </servlet-mapping>
    <welcome-file-list>
        <welcome-file>redirect.jsp</welcome-file>
    </welcome-file-list>

    <listener>
        <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
    </listener>

</web-app>

调度员的servlet

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"

    xmlns:mvc="http://www.springframework.org/schema/mvc"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
    xmlns:p="http://www.springframework.org/schema/p"
    xmlns:context="http://www.springframework.org/schema/context"
    xsi:schemaLocation="http://www.springframework.org/schema/beans 
    http://www.springframework.org/schema/beans/spring-beans.xsd
    http://www.springframework.org/schema/context 
    http://www.springframework.org/schema/context/spring-context.xsd
    http://www.springframework.org/schema/mvc
    http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd">


    <import resource="hibernate-context.xml" />


    <mvc:annotation-driven /> 

    <bean id="viewResolver"
          class="org.springframework.web.servlet.view.InternalResourceViewResolver" p:prefix="/WEB-INF/jsp/" p:suffix=".jsp" />

    <bean id="messageSource" class="org.springframework.context.support.ResourceBundleMessageSource" p:basename="messages" />

    <context:component-scan base-package="com.vaannila" />

    <bean id="userService" class="com.vaannila.service.UserServiceImpl" />

    <bean id="userValidator" class="com.vaannila.validator.UserValidator" />
     <bean id="registrationDAO" class="com.vaannila.dao.RegistrationDAO" />
     <bean id="userDAO" class="com.vaannila.dao.UserDAO" />





   <bean id="velocityEngine" class="org.springframework.ui.velocity.VelocityEngineFactoryBean">
      <property name="velocityProperties">
         <value>
          resource.loader=class
          class.resource.loader.class=org.apache.velocity.runtime.resource.loader.ClasspathResourceLoader
         </value>
      </property>
   </bean>



</beans>

休眠上下文

<?xml version="1.0" encoding="UTF-8"?>
<beans  xmlns="http://www.springframework.org/schema/beans" 
        xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
        xmlns:p="http://www.springframework.org/schema/p" 
        xmlns:tx="http://www.springframework.org/schema/tx"
        xmlns:context="http://www.springframework.org/schema/context"
        xsi:schemaLocation="
            http://www.springframework.org/schema/beans 
            http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
            http://www.springframework.org/schema/tx 
            http://www.springframework.org/schema/tx/spring-tx-3.0.xsd
            http://www.springframework.org/schema/context
            http://www.springframework.org/schema/context/spring-context-3.0.xsd
            ">

    <context:property-placeholder location="/WEB-INF/spring.properties" />

    <!-- Enable annotation style of managing transactions -->
    <tx:annotation-driven transaction-manager="transactionManager" />   

    <!-- Declare the Hibernate SessionFactory for retrieving Hibernate sessions -->
    <!-- See http://static.springsource.org/spring/docs/3.0.x/javadoc-api/org/springframework/orm/hibernate3/annotation/AnnotationSessionFactoryBean.html -->                           
    <!-- See http://docs.jboss.org/hibernate/stable/core/api/index.html?org/hibernate/SessionFactory.html -->
    <!-- See http://docs.jboss.org/hibernate/stable/core/api/index.html?org/hibernate/Session.html -->
    <bean id="sessionFactory" class="org.springframework.orm.hibernate3.annotation.AnnotationSessionFactoryBean"
                 p:dataSource-ref="dataSource"
                 p:configLocation="${hibernate.config}"
                 p:packagesToScan="com.vaannila"/>

    <!-- Declare a datasource that has pooling capabilities-->   
    <bean id="dataSource" class="com.mchange.v2.c3p0.ComboPooledDataSource"
                destroy-method="close"
                p:driverClass="${app.jdbc.driverClassName}"
                p:jdbcUrl="${app.jdbc.url}"
                p:user="${app.jdbc.username}"
                p:password="${app.jdbc.password}"
                p:acquireIncrement="5"
                p:idleConnectionTestPeriod="60"
                p:maxPoolSize="100"
                p:maxStatements="50"
                p:minPoolSize="10" />

    <!-- Declare a transaction manager-->
    <bean id="transactionManager" class="org.springframework.orm.hibernate3.HibernateTransactionManager" 
                p:sessionFactory-ref="sessionFactory" />

</beans>

Answer 1

不，那不行。新的SessionFactory将无法正确初始化（它缺少您在applicationContext.xml中设置的所有必需配置。）

因此，请确保您有一个名为sessionFactory和<context:component-scan .. />

的bean

另请注意，dispatcher-servlet.xml中定义的bean在applicationContext.xml

中定义的bean不可见

Answer 2

不，那不行。你可以使用spring的autowire功能。

如果您不想使用注释进行链接，请考虑使用application-context.xml链接（注入）您的sessionFactory。

Answer 3

您没有提供足够的背景信息。我甚至不明白你的问题是什么，也不知道什么不起作用。请显示一些配置和一些输出。

可是：

SessionFactory sessionFactory = new Sessionfactory()

如果您使用这样的代码，那么首先使用像Spring这样的IOC容器是没有意义的，因为您错过了关键概念，依赖注入。

没有布线使用弹簧豆的其他替代方法是什么

3 个答案: