Question

我想解组这样的（简化）XML结构：

<parent>
    <a>AValue</a>
    <b>BValue</b>
    <c someAttribute = "true">CValue</c>
</parent>

我知道如何像这样声明C类：

@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "c", propOrder = {
        "someAttribute"
    })
public class C{
    @XmlValue
    private String c;
    @XmlAttribute ( name="someAttribute")
    private boolean someAttribute;
    //getters and setters
}

并使其成为此类的父类成员：

public class Parent{
   private String a;
   private String b;
   private C c;
   //getters and setters for c,b,a
}

此作品被发现者，我可以通过C访问parent.getC().getC();的值我的问题是如何实现我不必创建类C 并获得value的{{1}}和attribute作为成员的问题（C的版本，而无需使用新成员以及其他getter和setter来编辑parent Pojo。我已经尝试通过侦听器执行此操作，并搜索了类似的结构，但是我没有任何想法。

Answer 1

I finally figured out how to achieve this. Its necessary to use the @XmlJavaTypeAdapter Annotation and mark the C class as an @XmlRootElement as well as an @XmlAccessorType(XmlAccessType.FIELD). Furthermore one need to use the @XmlTransient on the getter of the String member which was annotated with @XmlJavaTypeAdapter.

Full solution:

Class C:

@XmlRootElement
@XmlAccessorType(XmlAccessType.FIELD)
public class C{
    @XmlValue
    private String c;

    @XmlAttribute
    private boolean someAttribute;
    //getters and setters for both

Class Adapter:

public class Adapter extends XmlAdapter<C, String> {

    public String unmarshal(C pC) throws Exception {
        //some possible handling with the attribute over pC.getSomeAttribute();
        return pC.getC();
    }

    public C marshal(String pC) throws Exception {
       C c = new C();
       c.setC(pC)
       //some possible handling to set the attribute to c
       return c;
    }

Class Parent:

public class Parent{
   private String a;
   private String b;
   @XmlJavaTypeAdapter(Adapter.class)
   private String c;

   @XmlTransient
    public String getC() {
        return c;
    }
   //getters and setters for b,a and setter for C
}

JAXB取消编组子属性而不创建子类

1 个答案: