Question

我正在使用GeoFirestore在Firestore云上编写一个Cloud函数，以根据中心和半径查询附近的位置。

初始化代码如下

    const firebase = require('firebase');
    const admin = require('firebase-admin');
    const functions = require('firebase-functions');
    const GeoFirestore = require("geofirestore").GeoFirestore;
    admin.initializeApp(functions.config().firebase);
    const db = admin.firestore();

要查询的JS代码是

const object = db.collection('UserObject');
var geoFirestore = new GeoFirestore(object);
const geoQuery = geoFirestore.query({
    center: new firebase.firestore.GeoPoint(17.500362, 78.587374),
    radius: 1
});
geoQuery.on('ready', () => {
    var locations = geoQuery._locationsTracked;
    var keys = [];
    locations.forEach(function (locationMap, key) {
        if (typeof locationMap !== 'undefined' && locationMap.isInQuery) {
            keys.push(locationMap);
        }
    });
    response.status(200).json(keys);
  });

我是GeoFirestore库的新手。我的问题是，这是获取附近位置的合适方法还是使用此库查询附近位置的其他方法？

Answer 1

这种类型需要大量的修改，但是解决方案将更简单（注释中解释了代码）：

const object = db.collection('UserObject');
const geoFirestore = new GeoFirestore(object);
const geoQuery = geoFirestore.query({
  center: new firebase.firestore.GeoPoint(17.500362, 78.587374),
  radius: 1
});

// Where we will store the results
const results = [];

// As documents come in, push them into our results
geoQuery.on('key_entered', (key, document) => results.push(document));

// After the query is initially complete we then send the results to the client
geoQuery.on('ready', () => response.status(200).json(results));

使用GEOFirestore获取附近的GEO结果

1 个答案: