从Javascript中的XPATH获取数组中的值

时间:2018-12-21 19:05:11

标签: javascript xpath

如何获取从XPATH请求返回的对象的迭代值。

我有这个HTML模板:

<div class="item">
<span class="light">Date</span>
<a class="link" href="">2018</a>
(4pop)
</div>

<div class="item">
<span class="light">From</span>
<span>
<a class="link" href="" title="Bob" itemprop="url"><span itemprop="name">Bob</span></a>,
</span>
<span>
<a class="link" href="" title="Peter" itemprop="url"><span itemprop="name">Peter</span></a>
</span>
</div>

<div class="item">
<span class="light">For</span>
<a class="link" href="">Bak</a>,
<a class="link" href="">Cam</a>,
<a class="link" href="">Oli</a>
</div>

<div class="item">
<span class="light">Nat</span>
<a class="link" href="">Cool</a>
</div>
</div>    

还有我的Javascript代码:

var doc = new DOMParser().parseFromString(HTMLContent,'text/html');
var infos = doc.evaluate('//div[@class="item"]/span[1]', doc, null, XPathResult.ANY_TYPE, null);

var nodes = [];
for(var node = infos.iterateNext(); node; node = infos.iterateNext()) {
    nodes.push(node);
    console.log(node.textContent);

    // Until here, all things works well ! Except the code from here:
    var nodde = node.nextElementSibling.attributes;

    nodde.forEach(function(item){
        console.log(item);
    });
}

我的目标是获取每个类别的相应值,例如:

Date = 2018, (4pop)
From = Bob, Peter
For = Bak, Cam, Oli
Nat = Cool

我尝试迭代:node.nextElementSibling.attributes,但没有成功!

我尝试过的事情:

var nodde = node.nextElementSibling.attributes;
nodde.forEach(function(item){
    console.log(item);
});

您可以在Javascript代码上对其进行检查,但是很遗憾,这将导致空结果。

请问有没有办法得到预期的结果?

1 个答案:

答案 0 :(得分:1)

一旦获得商品,您就可以遍历childNodes,其中包括标签和文本。

var items = document.evaluate('//div[@class="item"]', doc, null, XPathResult.ANY_TYPE, null);
while (item = items.iterateNext()) {
    var values = [];
    var nodes = item.childNodes;
    for (var i = 2; i < nodes.length; i++) {
        var value = nodes[i].textContent.trim().replace(',', '');
        if (value.length) values.push(value);
    }
    console.log(item.getElementsByClassName('light')[0].innerText + " = " + values.join(', '));
}

打印:

Date = 2018, (4pop)
From = Bob, Peter
For = Bak, Cam, Oli
Nat = Cool