Question

我有两个输入字段，如下所示；

library(ggplot2)
library(dplyr)

m1 %>% 
  group_by(SEGMENT) %>% 
  top_n(10, Calculated_Potential) %>% 
  ggplot(aes(reorder(ACCOUNT_NAME, Calculated_Potential), Calculated_Potential/10^6)) + 
    geom_col() + 
    theme(axis.text.x = element_text(angle = -90, hjust = 0)) +
    facet_grid(~ SEGMENT, scales = "free_x")

如何使用foreach上传两个文件？我尝试了几种方法，但我无法实现。

谢谢

Answer 1

好吧，如果您坚持使用参数和输入名称来保持它不变，那么就必须在$_FILES之前重组do_upload()数组：

public function upload()
{
    $count = count($_FILES['datainfo']['name']);
    for ($i=0; $i < $count; $i++)
    {
        foreach ($_FILES['datainfo'] as $key1 => $value1)
        {
            foreach ($value1 as $key2 => $value2)
            {
                $files[$key2][$key1] = $value2;
            }
        }
    }
    $_FILES = $files;
    $config['upload_path'] = FCPATH.'uploads/';
    $config['allowed_types'] = 'gif|jpg|jpeg|png';
    $config['max_size'] = '2048';
    $config['max_width'] = '1920';
    $config['max_height'] = '1280';
    $this->load->library('upload', $config);
    foreach ($_FILES as $fieldname => $fileObject)
    {
        if (!empty($fileObject['name']))
        {
            $this->upload->initialize($config);
            if (!$this->upload->do_upload($fieldname))
            {
                $errors = $this->upload->display_errors();
            }
            else
            {
                 $success = 'Success';
            }
        }
    }
}

我已经在您输入的环境中对它进行了测试，并且效果很好。

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