Question

我无法从实体生成表。我在Mac OSX上使用Eclipse Photon，已成功与本地PostgreSQL数据库建立连接并成功测试了正确的ping。

现在，问题是当我单击“ JPA工具->从实体生成表”时，Eclipse没有执行任何操作。没有这样的错误消息，没有这样的信号。

我已经映射了我的实体，下面附上一些示例。

AccessDataEntity.java

@Entity
@Table(name = "access_data")
public class AccessDataEntity implements Serializable {

    private static final long serialVersionUID = 1L;

    @Id
    @GeneratedValue(strategy = GenerationType.SEQUENCE)
    private long id;

    @Column(name = "password", length = 15)
    private String password;

    @OneToOne
    private PersonalInformationEntity personalInformation;

    public long getId() {
        return id;
    }

    public void setId(long id) {
        this.id = id;
    }

    public String getPassword() {
        return password;
    }

    public void setPassword(String password) {
        this.password = password;
    }

    public PersonalInformationEntity getPersonalInformation() {
        return personalInformation;
    }

    public void setPersonalInformation(PersonalInformationEntity personalInformation) {
        this.personalInformation = personalInformation;
    }

    public static long getSerialversionuid() {
        return serialVersionUID;
    }

}

PersonalInformationEntity.java

@Entity
@Table(name = "personal_information")
public class PersonalInformationEntity implements Serializable {

    private static final long serialVersionUID = 1L;

    @Id
    @GeneratedValue(strategy = GenerationType.SEQUENCE)
    @Column(name = "id")
    private long id;

    @Column(name = "name", length = 30)
    private String name;

    @Column(name = "surname", length = 30)
    private String surname;

    @Column(name = "email", length = 20)
    private String email;

    @Column(name = "date_of_birth")
    private Date dateOfBirth;

    @OneToOne(mappedBy = "personalInformation", cascade = CascadeType.ALL, fetch = FetchType.LAZY, optional = false)
    private AccountEntity account;

    @OneToMany(mappedBy = "personalInformation", fetch = FetchType.LAZY)
    private List<PersonalGoalEntity> personalGoals;

    @OneToOne(mappedBy = "personalInformation", fetch = FetchType.LAZY)
    private AccessDataEntity accessData;

    public long getId() {
        return id;
    }

    public void setId(long id) {
        this.id = id;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public String getSurname() {
        return surname;
    }

    public void setSurname(String surname) {
        this.surname = surname;
    }

    public String getEmail() {
        return email;
    }

    public void setEmail(String email) {
        this.email = email;
    }

    public Date getDateOfBirth() {
        return dateOfBirth;
    }

    public void setDateOfBirth(Date dateOfBirth) {
        this.dateOfBirth = dateOfBirth;
    }

    public static long getSerialversionuid() {
        return serialVersionUID;
    }

    public AccountEntity getAccount() {
        return account;
    }

    public void setAccount(AccountEntity account) {
        this.account = account;
    }

    public List<PersonalGoalEntity> getPersonalGoals() {
        return personalGoals;
    }

    public void setPersonalGoals(List<PersonalGoalEntity> personalGoals) {
        this.personalGoals = personalGoals;
    }

}

我还配置了 persistence.xml 文件。

<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.1"
    xmlns="http://xmlns.jcp.org/xml/ns/persistence"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/persistence http://xmlns.jcp.org/xml/ns/persistence/persistence_2_1.xsd">
    <persistence-unit name="aster.jpa">
        <class>it.manuelgozzi.aster.jpa.entity.AccessDataEntity</class>
        <class>it.manuelgozzi.aster.jpa.entity.AccountEntity</class>
        <class>it.manuelgozzi.aster.jpa.entity.MovementEntity</class>
        <class>it.manuelgozzi.aster.jpa.entity.MovementGroupEntity</class>
        <class>it.manuelgozzi.aster.jpa.entity.PersonalGoalEntity</class>
        <class>it.manuelgozzi.aster.jpa.entity.PersonalInformationEntity</class>
        <properties>
            <property name="hibernate.hbm2ddl.auto" value="create-drop" />
            <property name="hibernate.dialect" value="org.hibernate.dialect.PostgreSQLDialect"/>
            <!-- <property name="hibernate.connection.driver_class" value="org.postgresql.Driver"/>
            <property name="hibernate.connection.url" value="jdbc:postgresql://localhost:3306/aster"/>
            <property name="hibernate.connection.password" value="postgres"/>
            <property name="hibernate.connection.username" value="1234"/> -->
            <property name="javax.persistence.jdbc.url" value="jdbc:postgresql://localhost:3306/aster"/>
            <property name="javax.persistence.jdbc.user" value="postgres"/>
            <property name="javax.persistence.jdbc.password" value="1234"/>
            <property name="javax.persistence.jdbc.driver" value="org.postgresql.Driver"/>
        </properties>
    </persistence-unit>
</persistence>

我想念什么？我测试了与数据库的连接，看来还可以，在测试ping时没有此类错误。我不明白为什么我什么都看不到。

我针对 Hibernate JPA 2.1 设置了连接配置文件。

Answer 1

我终于做到了。

我忘记在我的pom.xml中插入休眠依赖项。完成后，我配置了一个Hibernate Console，然后重试。

现在一切正常，我错过了最重要的一点...

Hibernate从实体生成表不起作用

1 个答案: