假设我从Django文档中获取以下代码:
class Student(models.Model):
FRESHMAN = 'FR'
SOPHOMORE = 'SO'
JUNIOR = 'JR'
SENIOR = 'SR'
YEAR_IN_SCHOOL_CHOICES = (
(FRESHMAN, 'Freshman'),
(SOPHOMORE, 'Sophomore'),
(JUNIOR, 'Junior'),
(SENIOR, 'Senior'),
)
year_in_school = models.CharField(
max_length=2,
choices=YEAR_IN_SCHOOL_CHOICES,
default=FRESHMAN,
)
但是我想做:
from student_app import choices
class Student(models.Model):
year_in_school = models.CharField(
max_length=2,
choices=choices.YEAR_IN_SCHOOL_CHOICES,
default=choices.FRESHMAN,
)
总有没有使用反射来确定从哪个模块导入选择?
例如:
field = Student._meta.fields.get_field_by_name('year_in_school')
choices_source = some_clever_function(field)
print("Choices imported from '%s'" % choices_source)
我希望输出为:
从“ student_app”导入的选择。
显然,聪明的功能不存在,但希望能阐明我要做什么。
谢谢