我有一个扩展名,可以捕获打开文件的文本并对其进行更改。更改文字后,如何将其放回VSCode中显示的文件中?
// this method is called when your extension is activated
// your extension is activated the very first time the command is executed
export function activate(context: vscode.ExtensionContext) {
// Use the console to output diagnostic information (console.log) and errors (console.error)
// This line of code will only be executed once when your extension is activated
console.log('Congratulations, your extension "myExtension" is now active!');
console.log(process.versions);
// The command has been defined in the package.json file
// Now provide the implementation of the command with registerCommand
// The commandId parameter must match the command field in package.json
let disposable = vscode.commands.registerCommand('extension.myExtension', () => {
// The code you place here will be executed every time your command is executed
let activeEditor = vscode.window.activeTextEditor;
if (!activeEditor) {
return;
}
let text = activeEditor.document.getText();
getAsyncApi(text).then( (textToInsertIntoDoc) => {
let finaldoc = insertTextIntoDoc(text, textToInsertIntoDoc);
// not what I want - just used to see new text
vscode.window.showInformationMessage(textToInsertIntoDoc);
});
});
context.subscriptions.push(disposable);
}
答案 0 :(得分:2)
您可以在此处使用的API为TextEditor.edit
,其定义为
edit(callback: (editBuilder: TextEditorEdit) => void, options?: { undoStopBefore: boolean; undoStopAfter: boolean; }): Thenable<boolean>;
它要求将回调作为第一个参数,并且在回调中,您可以通过访问editBuilder对文档进行编辑。
我在https://github.com/Microsoft/vscode-extension-samples/tree/master/document-editing-sample中放了一个示例扩展名,它可以颠倒当前选择中的内容,这基本上是一个简单的用法TextEditor.edit
。
答案 1 :(得分:1)
由于我在上述答案中提到的问题,我最终编写了一个快速的函数,该函数可以进行多光标友好的插入,并且如果选择为空,则它不会保留随后选择的插入文本(即具有与您按下 CTRL + V 或在键盘上键入文本等相同的直观行为。
调用很简单:
// x is the cursor index, it can be safely ignored if you don't need it.
InsertText(x => 'Hello World');
实施:
function InsertText(getText: (i:number) => string, i: number = 0, wasEmpty: boolean = false) {
let activeEditor = vscode.window.activeTextEditor;
if (!activeEditor) { return; }
let sels = activeEditor.selections;
if (i > 0 && wasEmpty)
{
sels[i - 1] = new vscode.Selection(sels[i - 1].end, sels[i - 1].end);
activeEditor.selections = sels; // required or the selection updates will be ignored! ?
}
if (i < 0 || i >= sels.length) { return; }
let isEmpty = sels[i].isEmpty;
activeEditor.edit(edit => edit.replace(sels[i], getText(i))).then(x => {
InsertText(getText, i + 1, isEmpty);
});
}
答案 2 :(得分:1)
这是Rebornix扩展示例(包含在Microsoft扩展示例集合中)的主要功能的修订版,该功能处理您提出的选择问题。它会反转选择内容(保留选择内容),或者如果选择为空,则会在该选择下的光标下方反转单词,而不会保留任何选择内容。离开选择通常很有意义,但是您可以添加代码以删除选择。
let disposable = vscode.commands.registerCommand('extension.reverseWord', function () {
// Get the active text editor
const editor = vscode.window.activeTextEditor;
if (editor) {
const document = editor.document;
editor.edit(editBuilder => {
editor.selections.forEach(sel => {
const range = sel.isEmpty ? document.getWordRangeAtPosition(sel.start) || sel : sel;
let word = document.getText(range);
let reversed = word.split('').reverse().join('');
editBuilder.replace(range, reversed);
})
}) // apply the (accumulated) replacement(s) (if multiple cursors/selections)
}
});
尽管我可以通过将.selection
设置为似乎不适用于.selections[i]
的新的空选择来删除单个选择。但是您可以进行多个更改,而无需首先进行选择。
您不想做的是通过代码进行选择,只是通过代码来更改文本。用户做出选择,而您没有做出选择(除非该功能的最终目的是做出选择)。
我遇到这个问题,是在寻找一种应用textEdit[]
数组的方法(通常由provideDocumentRangeFormattingEdits
回调函数返回)。如果您在数组中构建更改,则可以使用自己的函数将其应用于文档:
const { activeTextEditor } = vscode.window;
if (activeTextEditor) {
const { document } = activeTextEditor;
if (document) {
/*
build your textEdits similarly to the above with insert, delete, replace
but not within an editBuilder arrow function
const textEdits: vscode.TextEdit[] = [];
textEdits.push(vscode.TextEdit.replace(...));
textEdits.push(vscode.TextEdit.insert(...));
*/
const workEdits = new vscode.WorkspaceEdit();
workEdits.set(document.uri, textEdits); // give the edits
vscode.workspace.applyEdit(workEdits); // apply the edits
}
}
所以这是将编辑应用于文档的另一种方法。即使我使editBuilder示例在不选择文本的情况下也可以正常工作,但在其他情况下,我还是遇到了选择问题。 WorkspaceEdit不会选择更改。
答案 3 :(得分:1)
以下代码段将解决您的问题:
short