Question

我有一个Controller方法需要接受客户端发送的multipart/form-data作为POST请求。表单数据有2个部分。一个是序列化为application/json的对象，另一个是以application/octet-stream发送的照片文件。我的控制器上有一个方法，如下所示：

[AcceptVerbs(HttpVerbs.Post)]
void ActionResult Photos(PostItem post)
{
}

我可以通过Request.File获取文件而没有问题。但是PostItem为null。不知道为什么？任何想法

控制器代码：

/// <summary>
/// FeedsController
/// </summary>
public class FeedsController : FeedsBaseController
{
    [AcceptVerbs(HttpVerbs.Post)]
    public ActionResult Photos(FeedItem feedItem)
    {
        //Here the feedItem is always null. However Request.Files[0] gives me the file I need  
        var processor = new ActivityFeedsProcessor();
        processor.ProcessFeed(feedItem, Request.Files[0]);

        SetResponseCode(System.Net.HttpStatusCode.OK);
        return new EmptyResult();
    }

}

线路上的客户端请求如下所示：

{User Agent stuff}
Content-Type: multipart/form-data; boundary=8cdb3c15d07d36a

--8cdb3c15d07d36a
Content-Disposition: form-data; name="feedItem"
Content-Type: text/xml

{"UserId":1234567,"GroupId":123456,"PostType":"photos",
    "PublishTo":"store","CreatedTime":"2011-03-19 03:22:39Z"}

--8cdb3c15d07d36a
Content-Disposition: file; filename="testFile.txt"
ContentType: application/octet-stream

{bytes here. Removed for brevity}
--8cdb3c15d07d36a--

Answer 1

FeedItem班级是什么样的？对于我在帖子信息中看到的内容，它应该类似于：

public class FeedItem
{
    public int UserId { get; set; }
    public int GroupId { get; set; }
    public string PublishTo { get; set; }
    public string PostType { get; set; }
    public DateTime CreatedTime { get; set; }
}

否则不受约束。您可以尝试更改操作签名，看看是否有效：

[HttpPost] //AcceptVerbs(HttpVerbs.Post) is a thing of "the olden days"
public ActionResult Photos(int UserId, int GroupId, string PublishTo
    string PostType, DateTime CreatedTime)
{
    // do some work here
}

您甚至可以尝试在动作中添加HttpPostedFileBase参数：

[HttpPost]
public ActionResult Photos(int UserId, int GroupId, string PublishTo
    string PostType, DateTime CreatedTime, HttpPostedFileBase file)
{
    // the last param eliminates the need for Request.Files[0]
    var processor = new ActivityFeedsProcessor();
    processor.ProcessFeed(feedItem, file);

}

如果你真的感到疯狂和顽皮，请将HttpPostedFileBase添加到FeedItem：

public class FeedItem
{
    public int UserId { get; set; }
    public int GroupId { get; set; }
    public string PublishTo { get; set; }
    public string PostType { get; set; }
    public DateTime CreatedTime { get; set; }
    public HttpPostedFileBase File { get; set; }
}

这最后一段代码片段可能就是您想要的结果，但逐步细分可能对您有所帮助。

这个答案也可以帮助你顺利指出：ASP.NET MVC passing Model *together* with files back to controller

Answer 2

正如@Sergi所说，将HttpPostedFileBase文件参数添加到您的操作中我不知道MVC3但是对于1和2您必须在表单/视图中指定您将发布multipart / form-data，如下所示：< / p>

<% using (Html.BeginForm(MVC.Investigation.Step1(), FormMethod.Post, new { enctype = "multipart/form-data", id = "step1form" }))

这是在我的控制器中：

[HttpPost]
    [ValidateAntiForgeryToken]
    [Authorize(Roles = "Admin, Member, Delegate")]
    public virtual ActionResult Step1(InvestigationStep1Model model, HttpPostedFileBase renterAuthorisationFile)
    {
        if (_requesterUser == null) return RedirectToAction(MVC.Session.Logout());

        if (renterAuthorisationFile != null)
        {
            var maxLength = int.Parse(_configHelper.GetValue("maxRenterAuthorisationFileSize"));
            if (renterAuthorisationFile.ContentLength == 0)
            {
                ModelState.AddModelError("RenterAuthorisationFile", Resources.AttachAuthorizationInvalid);
            }
            else if (renterAuthorisationFile.ContentLength > maxLength * 1024 * 1204)
            {
                ModelState.AddModelError("RenterAuthorisationFile", string.Format(Resources.AttachAuthorizationTooBig, maxLength));
            }
        } 
        if(ModelState.IsValid)
        {
            if (renterAuthorisationFile != null && renterAuthorisationFile.ContentLength > 0)
            {
                var folder = _configHelper.GetValue("AuthorizationPath");
                var path = Server.MapPath("~/" + folder);
                model.RenterAuthorisationFile = renterAuthorisationFile.FileName;
                renterAuthorisationFile.SaveAs(Path.Combine(path, renterAuthorisationFile.FileName));
            }
            ...
            return RedirectToAction(MVC.Investigation.Step2());
        }
        return View(model);
    }

希望它有所帮助！

ASP.NET MVC。如何创建接受和multipart / form-data的Action方法

2 个答案: