Question

我正在尝试使用科学记数法将数字格式设置为10的指数。使用python 3将0.00123写为1.23x10 ^–3。

我发现这个很棒的功能可以打印1.23x10 ^ -3，但是如何用上标替换尖号？

def sci_notation(number, sig_fig=2):
    ret_string = "{0:.{1:d}e}".format(number, sig_fig)
    a,b = ret_string.split("e")
    b = int(b)         # removed leading "+" and strips leading zeros too.
    return a + "x10^" + str(b)

print(sci_notation(0.001234, sig_fig=2))      # Outputs 1.23x10^-3

此功能是从https://stackoverflow.com/a/29261252/8542513修改而来的。

我试图结合https://stackoverflow.com/a/8651690/8542513的答案来格式化上标，但是我不确定sympy如何与变量一起工作：

from sympy import pretty_print as pp, latex
from sympy.abc import a, b, n

def sci_notation(number, sig_fig=2):
  ret_string = "{0:.{1:d}e}".format(number, sig_fig)
  a,b = ret_string.split("e")
  b = int(b)             #removed leading "+" and strips leading zeros too.
  b = str(b)
  expr = a + "x10"**b    #Here's my problem
  pp(expr)               # default
  pp(expr, use_unicode=True)
  return latex(expr)

print(latex(sci_notation(0.001234, sig_fig=2)))

这将返回：TypeError：**或pow（）不支持的操作数类型：'str'和'int'

Answer 1

这是一个简单的解决方案：

def SuperScriptinate(number):
  return number.replace('0','⁰').replace('1','¹').replace('2','²').replace('3','³').replace('4','⁴').replace('5','⁵').replace('6','⁶').replace('7','⁷').replace('8','⁸').replace('9','⁹').replace('-','⁻')

def sci_notation(number, sig_fig=2):
    ret_string = "{0:.{1:d}e}".format(number, sig_fig)
    a,b = ret_string.split("e")
    b = int(b)         # removed leading "+" and strips leading zeros too.
    return a + "x10^" + SuperScriptinate(str(b))

Answer 2

我认为您的主要问题是how can the caret-exponent be replaced with a superscript?

如果您在Jupyter笔记本中使用python，有一种简单的方法：

  from IPython.display import display, Math, Latex

  # if the number is in scientific format already
  display(Math('2.14e-6'.replace('e', r'\times 10^{') + '}'))

  # if it is not:
  d = "%e" % (number)
  # then use the above form: display(Math(d.replace('e', r'\times ...

Python：具有上标指数的科学计数法

2 个答案: