Question

我有表格“ sales”和类似此方案的数据：

User    | Amount| Month
user a      100     1
user b      240     1
user c      120     1
user a      200     2
user b      130     2
user c      240     2

如何根据每月的总销售量获得前五名用户，我尝试使用这种查询，但始终显示错误

SELECT TOP10 USER, 
   SUM(amount) amount
    FROM   sales LIMIT 10
WHERE  MONTH BETWEEN 1 AND 12
GROUP BY sales
ORDER BY 2 DESC

结果应该是：

User a | 300
User b | 370
User c | 360

因此订单必须为：B，C，A

Answer 1

您可以在GROUP BY上进行User，并使用SUM(amount)获取每个用户的total_sales。现在，只需按total_sales的降序顺序对结果集进行排序，即可首先获得最高的销售额。

如果您只想获得前10名，我们可以使用LIMIT 10。

SELECT User, 
       SUM(amount) AS total_sales 
FROM sales 
WHERE MONTH BETWEEN 1 AND 12
GROUP BY User
ORDER BY total_sales DESC
LIMIT 10

Answer 2

您可以在下面尝试

SELECT USER, SUM(amount) amount
FROM   sales 
WHERE  MONTH BETWEEN 1 AND 12
GROUP BY USER
ORDER BY amount DESC

根据My Sql中的销售数量获取前10位用户数据

2 个答案: