Question

以下代码返回了不正确的产品。我希望我需要在AsyncMultiply函数中使用await术语，并尝试将其添加到所有行的前面，但这没有用。我该如何修复代码，以使该任务成为无阻塞且正确计算的任务？

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Answer 1

Task.Run返回一个Task，而您不必等待它完成。如果您使用的是C＃7.1（.net 4.7）或更高版本，则可以一直看到等待调用的对象：

        static int prod;
        public static async Task Main(string[] args)
        {
            Task running  = Task.Run(async () => { await AsyncMultiply(2, 3); });

            for (int i = 0; i < 10; i++)
            {
                Console.Write(i + " ");
                Thread.Sleep(100);
            }

            await running; // Wait for the previously abandoned task to run.


            Console.WriteLine();
            Console.WriteLine("Prod = " + prod);

            Console.Write("Press any key to continue . . . ");
            Console.ReadKey();
        }

        public static async Task DoSomethingAsync()
        {
            await Task.Delay(100);
        }

        public static async Task<int> AsyncMultiply(int a, int b)
        {
            Thread.Sleep(2000);
            prod = a * b;
            return prod;
        }

否则，您可以冻结当前线程，等待任务完成：

        static int prod;
        public static void Main(string[] args)
        {
            Task running  = Task.Run(async () => { await AsyncMultiply(2, 3); });

            for (int i = 0; i < 10; i++)
            {
                Console.Write(i + " ");
                Thread.Sleep(100);
            }

            running.Wait(); // Freeze thread and wait for task.


            Console.WriteLine();
            Console.WriteLine("Prod = " + prod);

            Console.Write("Press any key to continue . . . ");
            Console.ReadKey();
        }

        public static async Task DoSomethingAsync()
        {
            await Task.Delay(100);
        }

        public static async Task<int> AsyncMultiply(int a, int b)
        {
            Thread.Sleep(2000);
            prod = a * b;
            return prod;
        }

使用非阻塞任务

1 个答案: