Question

这类似于试图从另一个列表重新排序列表的其他发布，但这是试图从对象列表的属性中进行。 list_a的编号为1-5，而test_list对象列表也包含1-5的属性。我想将这些列表属性重新排列为list_a中的顺序。这是我的代码，请帮助：

class tests():
    def __init__(self,grade):
        self.grade = grade


test_list = []

for x in range(1,6):
    test_object = tests(x)
    test_list.append(test_object)

for x  in test_list:
    print(x.grade)

list_a = [5,3,2,1,4]

for x in [test_list]:
    test_list.append(sorted(x.grade,key=list_a.index))
print(test_list)

Answer 1

您可以定义合适的键并将字典用作键功能：

class tests():
    def __init__(self,grade):
        self.grade = grade

test_list = []

for x in range(1,6):
    test_object = tests(x)
    test_list.append(test_object)

for x  in test_list:
    print(x.grade, end = "  ")  # modified

print("")

list_a = [5,3,2,1,4]

# works because unique values, if you had dupes, only the last occurence would 
# be used for sorting
d_a = { val:pos for pos,val in enumerate(list_a,1)}

test_list.sort(key = lambda x: d_a[x.grade]) 

for x  in test_list:
    print(x.grade, end = "  ")

输出：

# before
1  2  3  4  5  

# after
5  3  2  1  4

Answer 2

您可以执行以下操作以根据字典查找进行排序：

test_cache = {}

for test in test_list:
    test_cache[test.grade] = test # store the object based on the test score

sorted_objects = []
for x in list_a:
    sorted_objects.append(test_cache.get(x)) # build the output list based on the score

print [test.grade for test in sorted_objects]

输出：

[5, 3, 2, 1, 4]

用另一个列表更改对象列表的顺序

2 个答案: