Question

我正在开发一个涉及解析的android应用程序。我想在android中将参数传递给url。我该怎么办？

Answer 1

请试一试。

HttpPost postMethod = new HttpPost("your url");
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();

nameValuePairs.add(new BasicNameValuePair("your parameter","parameter value"));
nameValuePairs.add(new BasicNameValuePair("your parameter","parameter value"));

postMethod.setEntity(new UrlEncodedFormEntity(nameValuePairs));
DefaultHttpClient hc = new DefaultHttpClient();

HttpResponse response = hc.execute(postMethod);

nameValuePairs用于在url中添加参数。

Answer 2

这里ya go（适用于分页）

    public void Execute(final Request request,final ClientCallBackHandler CallBack)
{
    new Thread(new Runnable(){
        @Override
        public void run() {

            HttpParams myParams = new BasicHttpParams();

            HttpConnectionParams.setConnectionTimeout(myParams, 10000);
            HttpConnectionParams.setSoTimeout(myParams, 10000);
            DefaultHttpClient httpClient = new DefaultHttpClient(myParams);
        //dunno if this is correct...
            if(CurrentConnection.SvUsr.length() > 0)
            {
                httpClient.getCredentialsProvider().setCredentials(
                        new AuthScope(CurrentConnection.SvUrl, 80, null, "Digest"),
                        new UsernamePasswordCredentials(CurrentConnection.SvUsr, CurrentConnection.SvPw));
            }
            HttpContext localContext = new BasicHttpContext();

            if(CurrentConnection != null)
            {




                HttpPost httpPost = new HttpPost(CurrentConnection.SvUrl);
                try {


                    List<NameValuePair> pairs = new ArrayList<NameValuePair>();
                    String blah =  SerializeRequest(request);
                    pairs.add(new BasicNameValuePair("request",blah));

                    httpPost.setEntity(new UrlEncodedFormEntity(pairs));

                } catch (UnsupportedEncodingException e) {
                    // TODO Auto-generated catch block
                    if(CallBack != null)
                    {
                        CallBack.SetStatus(ClientCallBackHandler.ENCODING_EXCEPTION);
                    }

                    return;
                }
                try {
                    if(CallBack != null)
                        CallBack.SetStatus(ClientCallBackHandler.HTTP_DID_START);

                    HttpResponse response = httpClient.execute(httpPost,localContext);
                    if(response != null)
                    {
                        if(CallBack != null)
                        {
                            CallBack.response = DeserializeResponse(EntityUtils.toString(response.getEntity()));

                            CallBack.SetStatus(ClientCallBackHandler.HTTP_DID_SUCCEED);                                 
                        }

                        return;
                    }
                    else
                    {
                        if(CallBack != null)
                        {
                            CallBack.SetStatus(ClientCallBackHandler.HTTP_DID_ERROR);
                        }

                        return;
                    }
                } catch (ClientProtocolException e) {
                    // TODO Auto-generated catch block
                    if(CallBack != null)
                    {
                        CallBack.SetStatus(ClientCallBackHandler.CLIENT_PROTOCOL_EXCEPTION);
                    }

                    e.printStackTrace();
                    return;
                } catch (IOException e) {
                    // TODO Auto-generated catch block
                    if(CallBack != null)
                    {
                        CallBack.SetStatus(ClientCallBackHandler.IO_EXCEPTION);
                    }                       
                    e.printStackTrace();
                    return;
                }
            }   

        }

    }).start();




}

serializeRequest（）方法将您的请求转换为服务可以理解的字符串...例如我的看起来像这样：

    public String SerializeRequest(Request request) {
    Gson gson = gsonb.create();
    String JScript = gson.toJson(request);
    Log.v(request.getClass().getName(),JScript);
    return JScript;
}

DeserializeResponse（）方法与此相反，所以在gson的情况下：

    public Response DeserializeResponse(String Jscript)
{
    Response response = null;

    try {

        JSONObject jsonObject = new JSONObject(Jscript);

        Gson gson = gsonb.create();
        response = gson.fromJson(jsonObject.toString(), Response.class);
               if(response.ClassName.compareTo("ExceptionResponse")==0)
            response = gson.fromJson(jsonObject.toString(), ExceptionResponse.class);           
    } catch (JSONException e) {
        // TODO Auto-generated catch block
        response = new ExceptionResponse();
        ((ExceptionResponse) response).Message = Jscript;
    }
    Log.v(response.getClass().getName(),Jscript);
    return response;
}

Answer 3

private void postData(final String param, final TextView tv) {

        RequestQueue rq = Volley.newRequestQueue(this);

        StringRequest postReq = new StringRequest(Request.Method.POST,
                "https://your URL",
                new Response.Listener<String>() {

                    @Override
                    public void onResponse(String response) {
                        tv.setText(response); // We set the response data in the
                                                // TextView
                        Toast.makeText(getApplicationContext(), "Response"+response,Toast.LENGTH_LONG).show();
                    }
                }, new Response.ErrorListener() {

                    @Override
                    public void onErrorResponse(VolleyError error) {
                        System.out.println("Error [" + error + "]");

                        Toast.makeText(getApplicationContext(), "No Internet!!!", Toast.LENGTH_LONG).show();

                    }
                }) {

            @Override
            protected Map<String, String> getParams() throws AuthFailureError {
                Map<String, String> params = new HashMap<String, String>();

                params.put("your key", "value");
                params.put("any callback methods", "value");
                params.put("any types", "value");
                return params;
            }

        };

        rq.add(postReq);

在android中将参数传递给url

3 个答案: