我合并了两个查询,查询从中返回3列(月份,计数,目标) 通过分别执行两个查询,它返回2条正确的记录。 但是使用UNION ALL,它只返回一个值:
我的查询
select s.month,COALESCE(max(s.count), NULL, 0) as count, COALESCE(max(s.targets), NULL, 0) as target from
(SELECT MONTHNAME(tm.meeting_date) as month, count(DISTINCT tm.meeting_id) as count, NULL as targets
FROM tig as t
left join tig_meeting as tm ON t.tig_code = tm.tig_code
WHERE tm.meeting_date IS NOT NULL AND tm.meeting_date != 0 AND t.school_district = 'Islamabad C3'
AND (tm.meeting_date BETWEEN "2018-07-01" AND "2018-09-30") AND tm.key_support <> 'QuarterlyTigMeetings' AND tm.key_support <> 'QTIG_by_SSA'
AND tm.key_support <> 'MTIG_by_SSA' AND tm.meeting_no NOT LIKE '%RF'
GROUP BY MONTH(tm.meeting_date)
UNION ALL
SELECT mpt.month, NULL as count, SUM(mpt.monthly_target) as targets
FROM meeting_plan_targets mpt
LEFT JOIN meeting_plans mp ON mp.id = mpt.meeting_plan_id
WHERE mp.district = 'Islamabad C3' AND mp.module_title = 1 AND mp.year = 2018 AND mp.quarter = "Quarter 4" GROUP BY mpt.month) s
group by MONTH(s.month)
作为参考,请检查附件图像
答案 0 :(得分:0)
您可以在下面尝试
select s.`month`,COALESCE(max(s.count),0) as count, COALESCE(max(s.targets),0) as target from
(
SELECT MONTHNAME(tm.meeting_date) as `month`,MONTH(tm.meeting_date) as monnum,count(DISTINCT tm.meeting_id) as count, NULL as targets
FROM tig as t
left join tig_meeting as tm ON t.tig_code = tm.tig_code
WHERE tm.meeting_date IS NOT NULL AND tm.meeting_date != 0 AND t.school_district = 'Islamabad C3'
AND (tm.meeting_date BETWEEN '2018-07-01' AND '2018-09-30') AND tm.key_support <> 'QuarterlyTigMeetings' AND tm.key_support <> 'QTIG_by_SSA'
AND tm.key_support <> 'MTIG_by_SSA' AND tm.meeting_no NOT LIKE '%RF'
GROUP BY MONTHNAME(tm.meeting_date),MONTH(tm.meeting_date)
UNION ALL
SELECT MONTHNAME(mpt.month), MONTH(mpt.month),NULL as count, SUM(mpt.monthly_target) as targets
FROM meeting_plan_targets mpt
LEFT JOIN meeting_plans mp ON mp.id = mpt.meeting_plan_id
WHERE mp.district = 'Islamabad C3' AND mp.module_title = 1 AND mp.year = 2018 AND mp.quarter = 'Quarter 4'
GROUP BY MONTHNAME(mpt.month),MONTH(mpt.month)
) s
group by s.`month`,monnum order by monnum
答案 1 :(得分:0)
s.month
是月份名称。 MONTH(s.month)
不起作用,因为MONTH()
函数期望其参数为日期或日期时间(或可解析为日期或日期时间的字符串),而不是月份名称。
改为使用GROUP BY s.month
。