Question

我在每个红色标记的时间段上都有信息（开始时间戳和结束时间戳）。

我想要实现的是：

最后一个期间也应包含合并期间的数量，如蓝色跨度所示。

我已经尝试过从最小值和最大值开始的每一分钟，但是我想这不是解决此问题的最佳方法。我实际上在这里没有想法了：（示例数据：

[0] => Array
    (
        [start] => 2018-11-8 09:00
        [startTimestamp] => 1541664000
        [finish] => 2018-11-8 15:00
        [finishTimestamp] => 1541685600
        [machine_id] => 1
    )

[1] => Array
    (
        [start] => 2018-11-8 01:30
        [startTimestamp] => 1541637000
        [finish] => 2018-11-8 05:30
        [finishTimestamp] => 1541651400
        [machine_id] => 1
    )

[2] => Array
    (
        [start] => 2018-11-8 10:00
        [startTimestamp] => 1541667600
        [finish] => 2018-11-8 18:30
        [finishTimestamp] => 1541698200
        [machine_id] => 4
    )

[3] => Array
    (
        [start] => 2018-11-8 09:00
        [startTimestamp] => 1541664000
        [finish] => 2018-11-8 15:00
        [finishTimestamp] => 1541685600
        [machine_id] => 5
    )

[4] => Array
    (
        [start] => 2018-11-8 01:30
        [startTimestamp] => 1541637000
        [finish] => 2018-11-8 05:30
        [finishTimestamp] => 1541651400
        [machine_id] => 5
    )

感谢@solarc

        $startEndTimes = [];
    foreach ($periodsData as $periodsDatum) {
        $startEndTimes[$periodsDatum['startTimestamp']]  = date('Y-m-d H:i:s', $periodsDatum['startTimestamp']);
        $startEndTimes[$periodsDatum['finishTimestamp']] = date('Y-m-d H:i:s', $periodsDatum['finishTimestamp']);
    }

    $split = [];
    foreach ($periodsData as $periodsDatum) {
        foreach ($startEndTimes as $timestamp => $dateTime) {
            if ($timestamp < $periodsDatum['finishTimestamp'] AND $timestamp > $periodsDatum['startTimestamp']) {
                $split[] = [
                    'machine_id'      => $periodsDatum['machine_id'],
                    'startTimestamp'  => $periodsDatum['startTimestamp'],
                    'finishTimestamp' => $timestamp,
                    'start'           => $periodsDatum['start'],
                    'finish'          => date('Y-n-j H:i:s', $timestamp),
                ];
                $split[] = [
                    'machine_id'      => $periodsDatum['machine_id'],
                    'startTimestamp'  => $timestamp,
                    'finishTimestamp' => $periodsDatum['finishTimestamp'],
                    'start'           => date('Y-n-j H:i:s', $timestamp),
                    'finish'          => $periodsDatum['finish'],
                ];
            }
        }
    }

Answer 1

设置一组所有开始和结束时间（无重复）
```
[01:30, 05:30, 09:00, 10:00, 14:00, 18:30]
```

如果每个块在其自己的开始时间和结束时间之间有时间间隔，则将其拆分（例如，从09:00到15:00的块被拆分为2：09:00到10:00，然后10:00至15:00）：

    - 01:30 to 05:30 (col 1)
    - 09:00 to 10:00 (col 1)
    - 10:00 to 15:00 (col 1)
    - 10:00 to 15:00 (col 2)
    - 15:00 to 18:30 (col 2)
    - 01:30 to 05:30 (col 3)
    - 09:00 to 10:00 (col 3)
    - 10:00 to 15:00 (col 3)
    - 10:00 to 15:00 (col 4)
    - 15:00 to 18:30 (col 4)

最后，计算跨列重复的块数：

    - 01:30 to 05:30 (2 times)
    - 09:00 to 10:00 (2 times)
    - 10:00 to 15:00 (4 times)
    - 15:00 to 18:30 (2 times)

合并时间段-PHP

1 个答案: