Question

我正在用Java创建一个棋盘游戏，并且试图编写一种方法来标记用户在游戏期间选择的对象（该对象代表棋盘上的图块）。该方法位于一个类中，该类设置单个Tile的值和在板上的位置。

我认为使用枚举类型是一个好主意，但是我不确定究竟如何实现它。在我的课程中，我有一些方法可以获取Tile在网格上的位置（行，列）及其代表的字母。

public class Tile {

  private final String letter; //holds the letter value of the tile
  private final int row;       //holds tile row index
  private final int column;

  public Tile(String l, int r, int c) {
    this.letter = l;           
    this.row = r;
    this.column = c;
  }

  //setter&getter methods 

  public String toString() {
    return this.getLetter()+" "+ this.getRow() +
         "," + this.getColumn();
  }

所以在这个类中，我也想编写一个方法来标记是否选择了tile对象...我在想，如果toString方法返回一条语句，那么可以用来表明选择了图块。或者...我应该怎么做。这是我到目前为止的内容：

public enum Status {CHOSEN, NOTCHOSEN};

public static void tileStatus(Status stat){
  switch(stat) {
    case CHOSEN: //something
       break;
    case NOTCHOSEN: //something
       break;
  }
}

Answer 1

您可以声明枚举是Tile类的实例成员

public class Tile {

  private final String letter; //holds the letter value of the tile
  private final int row;       //holds tile row index
  private final int column;
  private Status flag; // use getter and setter to set flag on using Status enum

  public Tile(String l, int r, int c) {
    this.letter = l;           
    this.row = r;
    this.column = c;
  }

  //setter&getter methods 

  public String toString() {
    return this.getLetter()+" "+ this.getRow() +
         "," + this.getColumn();
  }

Answer 2

向图块添加布尔值可以帮助您获得状态。由于只有两种可能的状态（选择的而不是未选择的），因此布尔值可能更有意义。也不要默认添加getter和setter。仅在需要它们时。请参阅"tell don't ask principle"

public class Tile {

  private final String letter; //holds the letter value of the tile
  private final int row;       //holds tile row index
  private final int column;
  private boolean isTileFlagged;

  public Tile(String l, int r, int c) {
    this.letter = l;           
    this.row = r;
    this.column = c;
    isTileFlagged = false; // May be false to being with
  }

 // add getters/setters only when necessary

  public void toggleFlaggedState(){
      isTileFlagged = !isTileFlagged;
  }

  public String toString() {
    return this.getLetter()+" "+ this.getRow() +
         "," + this.getColumn();
  }

 // add hashcode, equals if necessary

此外，如果枚举是必需的，则它可能是Tile类的内部状态，因为它的独立存在可能没有意义。

Answer 3

将enum作为class的成员变量和enum的方法。

像下面这样：-

package com.robo.lab;

public class Tile {

    private final String letter; // holds the letter value of the tile
    private final int row; // holds tile row index
    private final int column;
    private Status status;

    public Tile(String l, int r, int c,Status status) {
        this.letter = l;
        this.row = r;
        this.column = c;
        this.status=status;
    }

    // setter&getter methods

    public Status getStatus() {
        return status;
    }

    public void setStatus(Status status) {
        this.status = status;
    }

    public String toString() {
        return this.getLetter() + " " + this.getRow() + "," + this.getColumn()+","+this.getStatus();
    }

    public String getLetter() {
        return letter;
    }

    public int getRow() {
        return row;
    }

    public int getColumn() {
        return column;
    }
}


package com.robo.lab;

public enum Status {
    CHOSEN, NOTCHOSEN;

    public static void tileStatus(Status stat) {
        switch (stat) {
        case CHOSEN: // something
            break;
        case NOTCHOSEN: // something
            break;
        }
    }
}


package com.robo.lab;

public class Main {

    public static void main(String[] args) {
        // TODO Auto-generated method stub

        Tile obj1= new Tile("AUser", 1, 1,Status.CHOSEN);
        System.out.println(obj1.toString());
        Tile obj2= new Tile("BUser", 1, 1,Status.NOTCHOSEN);
        System.out.println(obj2.toString());

    }

}

如何使用枚举为对象分配标志

3 个答案: