XML序列化时出现C#错误“XML文档中存在错误(2,2)”

时间:2011-03-15 16:11:52

标签: c# xml-serialization

所有,我正在尝试序列化和反序列化类,并且反序列化失败。有大量类似的线程,但我无法解决这个问题。我收到以下错误“XML文档中存在错误(2,2)”内部期望“{”未被预期。“}”

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml.Serialization;

namespace XMLSerialization
{
 [System.Xml.Serialization.XmlRootAttribute(Namespace = "",
     IsNullable = false)] 
 public class Level
 {
  private String _name;
  private String _background;

  public Level() 
  {
   _name = "LEVEL_NAME";
   _background = "LEVEL_BACKGROUND_IMAGE";
  }

  [XmlAttribute("LevelName")]
  public String LevelName
  {
   get { return _name; }
   set { _name = value; }
  }

  [XmlAttribute("Background")]
  public String Background
  {
   get { return _background; }
   set { _background = value; }
  }
 }
}

这是我用于反序列化的代码。序列化正在发生,但反序列化没有经历。我认为我犯了一个小错误,但我无法解决这个问题!

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.IO;
using System.Xml.Serialization;

namespace XMLSerialization
{
 class Program
 {
  static void Main(string[] args)
  {
   Level oLevel1 = new Level();

   XmlSerializerNamespaces ns = new XmlSerializerNamespaces();
   ns.Add("", ""); 
   XmlSerializer serializer = new XmlSerializer(typeof(Level));
   TextWriter textWriter = new StreamWriter("Level1.xml");
   serializer.Serialize(textWriter, oLevel1, ns);
   textWriter.Close();

   Level oLevel2 = new Level();
   XmlSerializer deserializer = new XmlSerializer(typeof(List<Level>));
   TextReader textReader = new StreamReader("Level1.xml");
   oLevel2 = (Level)deserializer.Deserialize(textReader);
   textReader.Close();
  }
 }
}

2 个答案:

答案 0 :(得分:8)

我认为您需要更改行

XmlSerializer deserializer = new XmlSerializer(typeof(List<Level>));

XmlSerializer deserializer = new XmlSerializer(typeof(Level));

答案 1 :(得分:3)

您序列化了Level并正在尝试取消List<Level>