使用IP地址范围(JavaScript)过滤JSON

时间:2018-10-20 15:56:56

标签: javascript json search filter ip-address

我有一个JSON文件,其中每个JSON对象都有一个唯一的标识符( IP地址

给定IP地址范围时,我想根据给定范围过滤原始JSON并将其存储在新文件中。 (即IP地址在给定范围内的所有JSON对象)

JSON文件:

[{
    "Name": "SERVER1",
    "ipv4Address": "192.168.0.50",
    "OperatingSystem": [],
    "OperatingSystemServicePack": null,
    "OperatingSystemVersion": "6.3 (9600)"
},
{
    "Name": "SERVER2",
    "ipv4Address": "192.168.0.51",
    "OperatingSystem": [],
    "OperatingSystemServicePack": null,
    "OperatingSystemVersion": "6.3 (9600)"
},
{
    "Name": "SERVER3",
    "ipv4Address": "192.168.0.52",
    "OperatingSystem": [],
    "OperatingSystemServicePack": null,
    "OperatingSystemVersion": "6.3 (9600)"
},
{
    "Name": "SERVER4",
    "ipv4Address": "192.168.0.53",
    "OperatingSystem": [],
    "OperatingSystemServicePack": null,
    "OperatingSystemVersion": "6.3 (9600)"
},
{
    "Name": "SERVER5",
    "ipv4Address": "192.168.0.54",
    "OperatingSystem": [],
    "OperatingSystemServicePack": null,
    "OperatingSystemVersion": "6.3 (9600)"
}]

如果给定范围为192.168.0.52-192.168.0.54,则输出应为:

 [{
    "Name": "SERVER3",
    "ipv4Address": "192.168.0.52",
    "OperatingSystem": [],
    "OperatingSystemServicePack": null,
    "OperatingSystemVersion": "6.3 (9600)"
},
{
    "Name": "SERVER4",
    "ipv4Address": "192.168.0.53",
    "OperatingSystem": [],
    "OperatingSystemServicePack": null,
    "OperatingSystemVersion": "6.3 (9600)"
},
{
    "Name": "SERVER5",
    "ipv4Address": "192.168.0.54",
    "OperatingSystem": [],
    "OperatingSystemServicePack": null,
    "OperatingSystemVersion": "6.3 (9600)"
}]

1 个答案:

答案 0 :(得分:1)

使用以下代码段。

function isWithinRange(ip, lowerBound, upperBound) {

  // Put all IPs into one array for iterating and split all into their own 
  // array of segments
  var ips = [ip.split('.'), lowerBound.split('.'), upperBound.split('.')];

  // Convert all IPs to ints
  for(var i = 0; i < ips.length; i++) {

    // Typecast all segments of all ips to ints
    for(var j = 0; j < ips[i].length; j++) {
      ips[i][j] = parseInt(ips[i][j]);
    }

    // Bit shift each segment to make it easier to compare
    ips[i] = 
      (ips[i][0] << 24) + 
      (ips[i][1] << 16) + 
      (ips[i][2] << 8) + 
      (ips[i][3]);
  }

  // Do comparisons
  if(ips[0] >= ips[1] && ips[0] <= ips[2]) return true;

  return false;
}


var json = [{
    "Name": "SERVER1",
    "ipv4Address": "192.168.0.50",
    "OperatingSystem": [],
    "OperatingSystemServicePack": null,
    "OperatingSystemVersion": "6.3 (9600)"
},
{
    "Name": "SERVER2",
    "ipv4Address": "192.168.0.51",
    "OperatingSystem": [],
    "OperatingSystemServicePack": null,
    "OperatingSystemVersion": "6.3 (9600)"
},
{
    "Name": "SERVER3",
    "ipv4Address": "192.168.0.52",
    "OperatingSystem": [],
    "OperatingSystemServicePack": null,
    "OperatingSystemVersion": "6.3 (9600)"
},
{
    "Name": "SERVER4",
    "ipv4Address": "192.168.0.53",
    "OperatingSystem": [],
    "OperatingSystemServicePack": null,
    "OperatingSystemVersion": "6.3 (9600)"
},
{
    "Name": "SERVER5",
    "ipv4Address": "192.168.0.54",
    "OperatingSystem": [],
    "OperatingSystemServicePack": null,
    "OperatingSystemVersion": "6.3 (9600)"
}];


var newArr = [];
var lowerBound = '192.168.0.52';
var upperBound = '192.168.0.54';

json.forEach(function(item){
      var isInRange = isWithinRange(item.ipv4Address, lowerBound, upperBound);
      if(isInRange){ 
        newArr.push(item);
      }
});


console.log("new Array : ", newArr);

使用@SaltedBlowfish通过他的Bit Shifting公式提供的解决方案

ref:https://stackoverflow.com/a/29173281/4882013