Question

我正在使用Python进行作业，需要将降雨量与每个月相关联。我需要打印降雨量的高低月份，但是目前编写代码的方式只能打印实际数量，而不能打印与该数量对应的月份。我想我可以在enter_rainfall函数下将两者关联起来，但是不确定如何将两者关联起来。任何建议表示赞赏。

def main():

    months_list = ['January', 'February', 'March', 'April', 'May', 'June', 'July', 'August', 'September', 'October', 'November', 'December']
    rain = enter_rainfall()
    average = avg_rainfall(rain)
    lowhigh = low_High(rain)
    print(format(average, '.2f'))

def enter_rainfall():
    rain_fall = []
    months = 12

    for months_list in range(months):
        rain_amount = float(input('Please enter the amount of rain:',))
        rain_fall.append(rain_amount)



    return(rain_fall)


def avg_rainfall(rain):
    total = 0

    for value in rain:
        total += value
    average = total / len(rain)
    return(average)

def low_High(rain, months_list):
    low = min(rain)
    month = months_list[rain.index(low)]
    print(month)
    high = max(rain)
    print(high)





main()

Answer 1

致电low_High时，实际上并没有传递月份列表（month_list）。相反，您应该这样称呼它：low_High(rain, months_list)。当您打印最小值和最大值时，您可能要同时打印月份和月份值-现在，您要同时打印月份和月份的最小值和最大值。

def low_High(rain, months_list):
    low_val = min(rain)
    low_month = months_list[rain.index(low_val)]
    high_val = max(rain)
    high_month = months_list[rain.index(high_val)]
    print('{month} had the least amount of rain with {val}'.format(month=low_month, val=low_val))
    print('{month} had the most amount of rain with {val}'.format(month=high_month, val=high_val))

如果您想在提示用户时跟踪月份，则可以通过修改enter_rainfall来访问该数组：

def main():
...        
    rain = enter_rainfall(month_list)
...

def enter_rainfall(month_list)
    for month in month_list:
        rain_amount = float(input('Please enter the amount of rain for {month}:'.format(month=month),))
        rain_fall.append(rain_amount)
    ...

Answer 2

您可以设置一个字典，记录下相应月份的降雨，然后可以使用字典查找min和max > values以及使用keys

的关联月份

def enter_rainfall():
    months_list = ['January', 'February', 'March', 'April', 'May', 'June', 'July', 'August', 'September', 'October', 'November', 'December']
    rain_fall = {i: 0 for i in months_list}

    for k in rain_fall:
        rain_fall[k] += float(input('Please enter the amount of rain for {}: '.format(k)))

    return rain_fall

def low_High(dicta):
    all_rain = [v for v in dicta.values()]
    low = ([k for k in dicta if dicta[k] == min(all_rain)], min(all_rain))
    high = ([k for k in dicta if dicta[k] == max(all_rain)], max(all_rain))
    return low, high

x = enter_rainfall()
low, high = low_High(x)
print(low, high)

Please enter the amount of rain for January: 10
Please enter the amount of rain for February: 11
Please enter the amount of rain for March: 12
Please enter the amount of rain for April: 10
Please enter the amount of rain for May: 22
Please enter the amount of rain for June: 18
Please enter the amount of rain for July: 1
Please enter the amount of rain for August: 9
Please enter the amount of rain for September: 2 
Please enter the amount of rain for October: 22
Please enter the amount of rain for November: 8
Please enter the amount of rain for December: 10
(['July'], 1.0) (['May', 'October'], 22.0)

如果两个或两个月以上的降雨与max或min相同，则所有对应的月份都将返回列表中

Answer 3

print和return可以接受多次返回并打印字符串。您不需要限制数量。

您只需要这样更改main。

def enter_rainfall():
    rain_fall = []
    months = 12

    for months_list in range(months):
        rain_amount = float(input('Please enter the amount of rain:',))
        rain_fall.append(rain_amount)
        print(months_list,rain_amount)
        # it will print corresponding month and its rain amount.


    return(rain_fall)

需要在Python中关联两个列表

3 个答案: