Question

我想为特定范围内的项目过滤查询集。这就是我的模型的样子

class modelEmployee(models.Model):
    user = models.ForeignKey(User, on_delete=models.CASCADE, null=True, blank=True)
    location = models.PointField(srid=4326,max_length=40, blank=True,null=True) 
    objects = GeoManager()

现在这是我运行过滤器命令的方式。要退回90英里范围内的物品。

qset = modelEmployee.objects.filter(location__distance_lte=(someLocation, D(mi=90)))

结果返回一个距离实际上为223.732英里的项目，不应返回。

这是两个项目的位置

location A - lat: 47.628641 and long: -117.402997

location B - lat: 47.618337 and long: -122.205341

两者的距离b / w实际上是223.732英里。我一定过滤错了。关于我可能要去哪里的任何建议？

Answer 1

在文档geo spatial query中，您应该使用dwithin

您的示例应像这样使用它：

qset = modelEmployee.objects.filter(location__dwithin=(someLocation, D(mi=90)))

Answer 2

来自Django文档distance_lte用于返回模型，其中查找几何图形到几何图形字段的距离大于或等于给定的距离值。

qset = modelEmployee.objects.filter（location__distance_lte =（someLocation， D（m = 90）））

您可以使用dwithin进行查询。

qset = model.modelEmployee.objects.filter（poly__dwithin =（geom，D（m = 5）））

Answer 3

您可以尝试使用此ref（gis/db-api），希望它能按您想要的方式工作。

示例：

from django.contrib.gis.db import models
class SouthTexasCity(models.Model):
    name = models.CharField(max_length=30)
    # A projected coordinate system (only valid for South Texas!)
    # is used, units are in meters.
    point = models.PointField(srid=32140)

然后可以如下执行距离查询：

from django.contrib.gis.geos import GEOSGeometry
from django.contrib.gis.measure import D # ``D`` is a shortcut for ``Distance``
from geoapp.models import SouthTexasCity
# Distances will be calculated from this point, which does not have to be projected.
pnt = GEOSGeometry('POINT(-96.876369 29.905320)', srid=4326)
# If numeric parameter, units of field (meters in this case) are assumed.
qs = SouthTexasCity.objects.filter(point__distance_lte=(pnt, 7000))
# Find all Cities within 7 km, > 20 miles away, and > 100 chains away (an obscure unit)
qs = SouthTexasCity.objects.filter(point__distance_lte=(pnt, D(km=7)))
qs = SouthTexasCity.objects.filter(point__distance_gte=(pnt, D(mi=20)))
qs = SouthTexasCity.objects.filter(point__distance_gte=(pnt, D(chain=100)))

筛选PointField的查询集字段以查找特定距离范围内的项目不正确

3 个答案: