Question

请有人帮助您如何提示用户退出，如果他们拒绝，请返回并重新运行该程序？我对此非常头痛，互联网也无济于事。

这是我的代码：

print("Hello, this program will ask for two numbers, then show the product 
of those numbers that many times")

value = input("Please enter number")

value = int(value)

value2 = input("Please enter a second number")

value2 = int(value2)

for i in range(value*value2):
    print(value*value2)

    while True:
        answer = input("Do you wih to exit? Enter Yes or No:")
        if answer in ('No', 'Yes'):
            break
        print ("Invalid input.")
    if answer == 'No':
        continue
    else:
        print ("Goodbye")
        break

这只是乘法，然后显示总和次数，但是我不知道如何提示用户退出，如果他们拒绝则再次运行程序。我听说过将整个代码放在一个循环中，但是我尝试过，但没有成功。我可以帮忙吗？

Answer 1

您可以将其设为递归函数，并在用户回答“否”时执行循环。

例如：

def ask():
    print("Hello, this program will ask for two numbers, then show the product of those numbers that many times")

    value = input("Please enter number")

    value = int(value)

    value2 = input("Please enter a second number")

    value2 = int(value2)

    for i in range(value * value2):
        print(value * value2)
    answer = input("Do you wih to exit? Enter Yes or No:")
    if answer not in ('No', 'Yes'):
        print("Invalid input.")
    if answer == 'No':
        ask()
    else:
        print("Goodbye")
ask()

Answer 2

基于所写的答案，但未编写函数：这里的关键是您需要循环播放，直到用户输入“是”为止。您的while循环永远不会为假，因此您将永远提示。这是另一种解决方案（尽管@Ricky Kim有更多的Python答案）

answer=""
while answer!= "yes":
    print("Hello, this program will ask for two numbers, then show the product \
    of those numbers that many times")

    value = input("Please enter number")

    value = int(value)

    value2 = input("Please enter a second number")

    value2 = int(value2)

    for i in range(value*value2):
        print(value*value2)
    #use lower so that the user can enter "Yes" or "yes"
    answer = str.lower(input("Do you wih to exit? Enter Yes or No:"))
print ("Goodbye")

如果他们拒绝，我如何提示用户退出并重新启动程序

2 个答案: