Question

我正在尝试将sql ID记录插入php echo表单输入值中。通过输入字段（通过键入）手动插入的值显示良好。输入中的值（名为：potnik）未显示。是否因为回声内部或插入错误而将其忽略？

$sql3 = "
SELECT id, potnik_id, ura, naslov
FROM prevoznik 
ORDER BY HOUR(ura), MINUTE(ura) ASC;
";
$result = $conn->query($sql3);

if ($result->num_rows > 0) {
    // output data of each row
    while($row = $result->fetch_assoc()) {

        //Spremenjena oblika datuma
        $date = date_create($row["ura"]);
        $ura_pobiranja = date_format($date,"H:i");
        echo "<div class=\"row list  divider-gray\">
                <div class=\"col-1 fs-09 fw-600\">" . $row["id"] . " </div>
                  <div class=\"col-3 flex-vcenter-items fw-600 fs-09\">" . $row["naslov"] . " </div>
                <div class=\"col-1 flex-vcenter-items fw-600 fs-09\">$ura_pobiranja</div>
            ";

        if ($row["naslov"] !== null) {
            echo " <div class=\"col-6 flex-vcenter-items fs-1\">Nastavi uro<form action='update.php?id=" . $row["id"] . "\"' method='POST'><input name=\"potnik\"  value='".$row["id"]."' type='hidden' /> <input class=\"form-control fancy-border\" type=\"text\" name=\"posodobljeni_cas\"/><input type='submit' value='Posodobi'>  </form></div>";
            echo " </div>";
        }
        else {
            echo " </div>";
        }

    }
} else {
    echo "<div class=\"col flex-vcenter-items fw-100 fs-1\"><i class=\"far fa-frown-open pr-3\"></i>Nimaš še nobenih opravil
                                    </div>";
}

无效的代码（隐藏的输入字段值）：

echo " <form action='update.php?id=" . $row["id"] . "\"' method='POST'><input name=\"potnik\"  value='".$row["id"]."' type='hidden' /> <input class=\"form-control fancy-border\" type=\"text\" name=\"posodobljeni_cas\"/><input type='submit' value='Posodobi'>  </form></div>";

Answer 1

我为update.php表单操作设置了发布参数，而不是获取参数

update.php？id =

echo"Error on update ID:{$_GET['id']} POSODOBLJENI CAS:{$_POST['posodobljeni_cas']}";

将php sql行记录插入隐藏的表单输入值字段

1 个答案: