Question

我对我的代码中的语法错误（我猜想）有疑问。在测试时，我突然收到一条消息，说我的行中缺少括号。这是它的样子。实际上，我试图从我的数据库中获取信息，然后通过socket.io将其附加到我的前端。该代码中的错误在第3行上。

socket.on('matchoverview', function(data){

  var $item1 = $("<div class='grid-item'><div class='row justify-content-md-center'><div class='col col-lg-1'></div><div class='col-lg-10'><div class='row'><div class='col-sm-3'><h3 id='insertteam1'><button id="" type='button' class='btn btn-dark'>Dark</button>" + data.teamonename + "</h3></div><div class='col-sm-3'><h3 id='insertpic1'>" + '<img id="logo" src=' + data.onelogo + '></img>' + "</h3></div><div class='col-sm-2'><h3 id='insertodd1'>" + data.teamoneodd + "</h3></div><div class='col-sm-2'><h3 id='insertclock'>" + data.time + "</h3></div><div class='col-sm-3'><h3 id='insertodd2'>" + data.teamtwoodd + "</h3></div><div class='col-sm-3'><h3 id='insertpic2'>" + '<img id="logo" src=' + data.twologo + '></img>' + "</h3></div><div class='col-sm-2'><h3 id='inserteam2'>" + data.teamtwoname + "</h3></div><div class='col-sm-2'><h3 id='inserttwitch'>" + data.twitchlink + "</h3></div></div></div></div></div>").click(function() {
    console.log('Jo!');
  });

  var $item2 = $("<div class='grid-item'><div class='row justify-content-md-center'><div class='col col-lg-1'></div><div class='col-lg-10'><div class='row'><div class='col-sm-3'><h3 id='insertteam1'><button id="" type='button' class='btn btn-dark'>Dark</button>" + data.teamonename + "</h3></div><div class='col-sm-3'><h3 id='insertpic1'>" + '<img id="logo" src=' + data.onelogo + '></img>' + "</h3></div><div class='col-sm-2'><h3 id='insertodd1'>" + data.teamoneodd + "</h3></div><div class='col-sm-2'><h3 id='insertclock'>" + data.time + "</h3></div><div class='col-sm-3'><h3 id='insertodd2'>" + data.teamtwoodd + "</h3></div><div class='col-sm-3'><h3 id='insertpic2'>" + '<img id="logo" src=' + data.twologo + '></img>' + "</h3></div><div class='col-sm-2'><h3 id='inserteam2'>" + data.teamtwoname + "</h3></div><div class='col-sm-2'><h3 id='inserttwitch'>" + data.twitchlink + "</h3></div></div></div></div></div>").click(function() {
    console.log('Jo!');
  });

  $grid2.append( $item1 ).masonry( 'appended', $item1 );
  $grid2.append( $item2 ).masonry( 'appended', $item2 );

});

错误代码：

Uncaught SyntaxError: missing ) after argument list

预先感谢，祝您愉快

Answer 1

请确保您的字符串定界符已正确放置并放置。

在“”和“”上出现

<button id=""

到

<button id=''

和您的

src='+variable+'

必须为

src='" +variable+ "'

谢谢！

我的代码中的方括号有问题

1 个答案: