Question

我正在尝试使用reactor，reactor.ipc.netty.http.client.HttpClient进行一些缓存，并使用lombok的@Getter(lazy = true)将其初始化为惰性getter字段。

在此代码段中，所有操作都可以在Java 8上正常运行，但无法在Java 10上使用error: incompatible types: Duration cannot be converted to String进行编译

@Value
public static class Translations {

    Map<String, Translation> translations;

    @Value
    public static class Translation {

        Map<String, String> content;

    }
}

@Getter(lazy = true)
Mono<Map<String, Translations.Translation>> translations = httpClient
        .get(String.format("%s/translations/%s", endpoint, translationGroup), Function.identity())
        .flatMap(it -> it.receive().aggregate().asByteArray())
        .map(byteArray -> {
            try {
                return objectMapper.readValue(byteArray, Translations.class);
            } catch (IOException e) {
                throw new UncheckedIOException("Failed to get translation for " + translationGroup, e);
            }
        })
        .map(Translations::getTranslations)
        .retryWhen(it -> it.delayElements(Duration.ofMillis(200)))
        .cache(Duration.ofMinutes(5))
        .timeout(Duration.ofSeconds(10));

但是用

编译就可以了

@Getter(lazy = true)
Mono<Map<String, Translations.Translation>> translations = Mono.just(new byte[]{})
        .map(byteArray -> {
            try {
                return objectMapper.readValue(byteArray, Translations.class);
            } catch (IOException e) {
                throw new UncheckedIOException("Failed to get translation for " + translationGroup, e);
            }
        })
        .map(Translations::getTranslations)
        .retryWhen(it -> it.delayElements(Duration.ofMillis(200)))
        .cache(Duration.ofMinutes(5))
        .timeout(Duration.ofSeconds(10));

如何知道出了什么问题以及如何解决？

Answer 1

我建议将初始化代码移至单独的方法。

@Getter(lazy=true)
SomeType t = <complicatedInitializationCode>;

成为

@Getter(lazy=true)
SomeType t = initializeT();

private SomeType initializeT() {
    return <complicatedInitializationCode>;
}

披露：我是lombok开发人员。

在Java 10中使用lombok.Getter（lazy = true）使用不兼容的类型错误

1 个答案: