Question

我正在用Spring创建RESTful WS。现在，对于每个WS，我都会为几个对象创建新的类。对于端点，我将这些类用作请求数据，而Jackson会自动将其转换，但是如果我只想将该对象的几个字段用于另一个端点，该怎么办？我不想为此创建另一个类。

例如，我有一个模型：

public class Salary {

    /*
     * Request Params
     */
    @JsonProperty("ID")
    private String documentId;

    @JsonProperty("DOCUMENTDATE")
    private Date createdDate;

    @JsonProperty("DOCUMENTNUMBER")
    private String documentNumber;

    @JsonProperty("PAYERACCOUNT")
    private String payer;

    @JsonProperty("RECEIVERACCOUNT")
    private String receiver;

    @JsonProperty("AMOUNT")
    private Double amount;

    @JsonProperty("CURRCODE")
    private String currency;

    @JsonProperty("GROUND")
    private String ground;

    /* Getters & Setters */
    // etc
}

终点：

@PostMapping("salaries")
public Response createSalary(@RequestBody Salary salary) {
    return salaryManager.createSalary(salary);
}

// There I want to use not the whole fields of Salary, but only documentDate and documentNumber
@PostMapping("salaries/transfer")
public Response transferSalary(@RequestBody Salary salary) {
    return salaryManager.transferSalary(salary);
}

因此，在上面的示例中，我在第二个端点中仅接受Salary类的少数几个参数作为请求。

Answer 1

假设您具有以下json，并且您不希望电机具有所有属性，

 { 
       "name": "kia",
       "motor": {
          "created_date": "2017-01-01",
          "size": "1L",
          "power": "44kw",
       },
       "model": "rio",
       "country": "south korea",
       "currency": "USD",
       "price": "14000"
 }

您可以将DTO中的motor属性建模为String，例如：

public class Car {

   public String name;
   // define the attribute, that you want to save flat as a String.
   private String motor;

   //or define specific attributes of the motor, that you want to parse.
   private String motorPower;

   // use the map as input and parse only the attributes that you need.
   @JsonProperty("motor")
   public String parseMotorAttributes(Map<String,Object> motorInfo) {
      StringBuilder sb = new StringBuilder();
      sb.append("size: ")
        .append((String)motorInfo.get("size"));

      this.motor = sb.toString();

      //set the concrete attributes you defined
      this.motorPower = (String)motorInfo.get("power");
      return this.motor;
   }

   public String country;

   public String currency;

   public String price;

}

Answer 2

我不知道这是一个合适的解决方案，但是我只是希望像往常一样在请求中找到相同的对象，然后我只是验证所需的字段而已。

如何仅将对象的几个字段用于REST服务

2 个答案: