me = User.query.filter_by(username=me)
them = User.query.filter_by(username=them)
my_friends = me.friends.all()
their_friends = them.friends.all()
如果my_friends返回['user1', 'user2', 'user3', 'user4']
和their_friends返回['user1', 'user2', 'user3']
如何获得两个用户之间的共同朋友？
我可以使用
list(set(my_friends).intersection(their_friends))
但是我宁愿通过SQL来完成。
答案 0 :(得分：0)
.btn-new:active, .btn-roll:active, .btn-hold:active {
margin: 2px 0 -2px 0;
}
.btn-style {
font-family: 'Montserrat', sans-serif;
font-weight: 300;
color: #5C5C5C;
background: none;
outline: none;
border: none;
margin: 0;
}
.btn-new {
position: absolute;
left: 50%;
transform: translate(-50%, -50%);
top: 30px;
font-size: 25px;
}
.btn-roll {
position: absolute;
left: 50%;
transform: translate(-50%, -50%);
top: 370px;
font-size: 25px;
}
.btn-hold {
position: absolute;
left: 50%;
transform: translate(-50%, -50%);
top: 415px;
font-size: 25px;
}
button:hover {
color: black;
}
.btn-new:active, .btn-roll:active, .btn-hold:active {
margin: 2px 0 -2px 0;
}
<button type="button" class="btn-new btn-style">New Game</button>
<button type="button" class="btn-roll btn-style">Roll Dice</button>
<button type="button" class="btn-hold btn-style">Hold</button>
me = User.query.filter_by(username=me)
them = User.query.filter_by(username=them)
是我所需要的。