Question

我正在为特定的时间范围创建TSQL参数，例如MorningTimeFrame将从昨天下午4点拉到今天中午，而AfternoonTimeFrame从今天下午拉到今天4Pm。我该如何设置？我熟悉Dateadd（day，datediff（day，1，GETDATE（）），0），但不确定如何将其设置为特定时间。

Answer 1

您可以根据以下查询获取这些所需的时间范围值

Select Cast(Cast(CAST(dateadd(d,-1,getdate()) AS date) as varchar) + ' 16:00:00' as datetime)AS 'MorningStartTime', Cast(Cast(CAST(getdate() AS date) as varchar) + ' 12:00:00' as datetime)AS 'MorningEndAfterNoonStartTime', Cast(Cast(CAST(getdate() AS date) as varchar) + ' 16:00:00' as datetime)AS 'AfterNoonEndTime'

为方便起见使用此

Answer 2

简单一些就够了吗？

declare @Start as DateTime, @End as DateTime;
declare @Timeframe as VarChar(32) = 'MorningTimeframe';

-- Start from midnight today.
declare @Today as DateTime = Cast( GetDate() as Date );

-- Calculate the timeframe.
if @Timeframe = 'MorningTimeframe'
  begin -- Yesterday 4PM through noon today.
  select @Start = DateAdd( hour, -8, @Today ),
    @End = DateAdd( hour, 12, @Today );
  end
else if @Timeframe = 'AfternoonTimeframe'
  begin -- Noon today through 4PM.
  select @Start = DateAdd( hour, 12, @Today ),
    @End = DateAdd( hour, 16, @Today );
  end
else
  begin
  RaIsError( 'Unexpected timeframe: ''%s''', 16, 42, @Timeframe );
  end;

-- Display the results.
select @Today as [Today], @Timeframe as Timeframe, @Start as [Start], @End as [End];

特定时间范围（前一天下午4PM到今天中午）的TSQL参数？

2 个答案: