Question

我有很多对很多类型的模型。我使用脚本来填充数据库。但是，我只想在使用y/n样式输入保存对象的情况下打印并保存它们。问题是我无法创建对象而不保存它们，如下所示。

>>> mov = Movie(name="completenothing")
>>> direc = Director(name="Someone")
>>> direc.movie_name.add(mov)
Traceback (most recent call last):
  File "<console>", line 1, in <module>
  File "/home/username/Code/virtualenvironments/matrix/local/lib/python2.7/site-packages/django/db/models/fields/related_descriptors.py", line 513, in __get__
    return self.related_manager_cls(instance)
  File "/home/username/Code/virtualenvironments/matrix/local/lib/python2.7/site-packages/django/db/models/fields/related_descriptors.py", line 830, in __init__
    (instance, self.pk_field_names[self.source_field_name]))
ValueError: "<Director: Someone>" needs to have a value for field "id" before this many-to-many relationship can be used.
>>> direc.save()
>>> direc.movie_name.add(mov)
Traceback (most recent call last):
  File "<console>", line 1, in <module>
  File "/home/username/Code/virtualenvironments/matrix/local/lib/python2.7/site-packages/django/db/models/fields/related_descriptors.py", line 934, in add
    self._add_items(self.source_field_name, self.target_field_name, *objs)
  File "/home/username/Code/virtualenvironments/matrix/local/lib/python2.7/site-packages/django/db/models/fields/related_descriptors.py", line 1060, in _add_items
    (obj, self.instance._state.db, obj._state.db)
ValueError: Cannot add "<Movie: completenothing N/A>": instance is on database "default", value is on database "None"
>>> mov.save()
>>> direc.movie_name.add(mov)

导演和电影之间存在多对多关系，我希望在保存之前显示其信息。是否有某种机制可以允许这样做？

Answer 1

如果您使用pre_save信号，可以尝试一下。

from django.db.models.signals import pre_save



def confirm_save(sender, instance, **kwargs):

    # do something with your instance (display information)  

    ans = input("Do you want to save(y/n)")


    if ans == 'y':
        print("Your instance saved successfully")

    else:
        raise Exception("Not saved")

pre_save.connect(confirm_save, sender=MyModel)

保存模型而不在Django中写入数据库

1 个答案: