Question

我正在尝试使用几个组件模板来构建YAML文档。我正在加载它们，构建一个Python对象，然后尝试转储它们（最终保存到文件中，但此示例仅打印出来）。正如您在下面看到的，它正在打印引用和指针，而不是我期望的字符串数据。我在做什么错（或不做什么）？

这是我用来说明我的问题的示例：

import yaml

main_template = yaml.load('organization: main')

sub_template = yaml.load('''
division: development
other:
  data:
  - for: users
''')

users = [ 'alice', 'bob', 'kim' ]

all_user_data = dict(main_template)

user_list = []

for user in users:
    tmp = dict(sub_template)
    tmp['name'] = user
    user_list.append(tmp)

all_user_data['users'] = user_list
print(yaml.dump(all_user_data, default_flow_style=False))

这将产生：

organization: main
users:
- division: development
  name: alice
  other: &id001
    data:
    - for: users
- division: development
  name: bob
  other: *id001
- division: development
  name: kim
  other: *id001

我期望这样的输出：

organization: main
users:
- division: development
  name: alice
  other:
    data:
    - for: users
- division: development
  name: bob
  other:
    data:
    - for: users
- division: development
  name: kim
  other:
    data:
    - for: users

Answer 1

正如Anthon在Avoid references in PyYAML中建议的那样，您可以

yaml.Dumper.ignore_aliases = lambda *args : True

然后

print(yaml.dump(all_user_data, default_flow_style=False))

收益

organization: main
users:
- division: development
  name: alice
  other:
    data:
    - for: users
- division: development
  name: bob
  other:
    data:
    - for: users
- division: development
  name: kim
  other:
    data:
    - for: users

我不知道为什么会这样。感谢安通。

橄榄

Python YAML转储指针引用

1 个答案: