Question

我有一个方法：

protected function validateLogin(Request $request)
{
    $this->validate($request, [
        'email' => 'required|string|exists:users,email,active,1,online,0',
        'password' => 'required|string',
    ], [
        'password.required' => 'Password required!',
        'email.exists' => 'Email not found!',
    ]);
}

验证“用户”表中的数据库中是否存在具有特定电子邮件地址的用户，该用户处于活动状态且未登录。 “用户”表的架构如下：

Schema::create($this->table, function (Blueprint $table) {
    $table->increments('id');
    $table->string('first_name');
    $table->string('last_name');
    $table->string('email')->unique();
    $table->string('password');
    $table->boolean('active')->default(true);
    $table->boolean('online')->default(false);
    $table->timestamps();
});

我想根据用户状态（在线|活动）返回错误消息

你能告诉我我该怎么做吗？我尝试过：

protected function validateLogin(Request $request)
{
    $this->validate($request, [
        'email' => 'required|string|exists:users,email,active,1,online,0',
        'password' => 'required|string',
    ], [
        'password.required' => 'Password required!',
        'email.exists' => 'Email not found!',
        'email.active' => 'User not active!',
        'email.online' => 'Email is onlone!',
    ]);
}

Answer 1

我真的不知道exists:users,email,active,1,online,0是否有效。我将从数据库中获取活动或在线字段，然后相应地返回一条消息。

Answer 2

首先，您需要提供FormRequest的解决方案，如以下代码段所示：

namespace App\Http\Requests;

use Illuminate\Support\Facades\Auth;

/**
 * Class UserRequest
 * @package App\Http\Requests
 */
class UserRequest extends Request
{
    /**
     * Determine if the user is authorized to make this request.
     *
     * @return bool
     */
    public function authorize()
    {
        return !Auth::check();
    }

    /**
     * Get the validation rules that apply to the request.
     *
     * @return array
     */
    public function rules()
    {
        return [
            'email' => 'required|unique:users|email_active:email@me.com|email_online:email@me.com',
            'password' => 'required|string|between:4,40'
        ];
    }

    public function messages()
    {
        return [
            'email.required' => 'Email is required',
            'email.unique' => 'This Email is already in use',
            'email.email_active' => 'This email is not active',
            'email.email_online' => 'This email is online',
            'password.required' => 'Password is required',
            'password.between' => 'Password length should be between :min and :max characters'
        ];
    }
}

email_active和email_online是两个不适用于Laravel框的规则。您应该通过php artisan make：rule EmailActiveRule和php artisan make：rule EmailOnlineRule创建它们。

这样做之后，您需要按照此答案的步骤来扩展规则

形成规则后，您需要通过存储库或模型检查数据库中的记录。

希望此解决方案对您有用。

Laravel 5.5验证消息

2 个答案: