Question

我有两列工作日，像这样在这些工作日之间的天数：

Monday  | Saturday    | 13
Tuesday | Friday      | 54
Friday  | Wednesday   | 10

等我需要使用SQL来创建另一个包含包含两个工作日之间所有13或54个工作日的字符串的列。类似于“星期一，星期二，星期三，...星期一，星期二...星期五，星期六”

这如何完成？谢谢。

Answer 1

以下是用于BigQuery标准SQL

#standardSQL
SELECT start, duration,
  REGEXP_EXTRACT(
    REPEAT('Monday,Tuesday,Wednesday,Thursday,Friday,Saturday,Sunday,',CAST(duration/7+1 AS INT64)),
    CONCAT(r'', start, r'(?:(?:,\w+){', CAST(duration - 1 AS STRING), '})')
  ) days_list
FROM `project.dataset.table`

您可以使用以下问题中的虚拟数据来测试/玩游戏

#standardSQL
WITH `project.dataset.table` AS (
  SELECT 'Monday' start, 'Saturday' finish, 13 duration UNION ALL
  SELECT 'Tuesday', 'Friday', 54 UNION ALL
  SELECT 'Friday', 'Wednesday', 10 
)
SELECT start, duration,
  REGEXP_EXTRACT(
    REPEAT('Monday,Tuesday,Wednesday,Thursday,Friday,Saturday,Sunday,', CAST(duration / 7 + 1 AS INT64) ), 
    CONCAT(r'', start, r'(?:(?:,\w+){', CAST(duration - 1 AS STRING), '})')
  ) days_list
FROM `project.dataset.table`

结果为

Row start   duration    days_list    
1   Monday  13  Monday,Tuesday,Wednesday,Thursday,Friday,Saturday,Sunday,Monday,Tuesday,Wednesday,Thursday,Friday,Saturday   
2   Tuesday 54  Tuesday,Wednesday,Thursday,Friday,Saturday,Sunday,Monday,Tuesday,Wednesday,Thursday,Friday,Saturday,Sunday,Monday,Tuesday,Wednesday,Thursday,Friday,Saturday,Sunday,Monday,Tuesday,Wednesday,Thursday,Friday,Saturday,Sunday,Monday,Tuesday,Wednesday,Thursday,Friday,Saturday,Sunday,Monday,Tuesday,Wednesday,Thursday,Friday,Saturday,Sunday,Monday,Tuesday,Wednesday,Thursday,Friday,Saturday,Sunday,Monday,Tuesday,Wednesday,Thursday,Friday,Saturday    
3   Friday  10  Friday,Saturday,Sunday,Monday,Tuesday,Wednesday,Thursday,Friday,Saturday,Sunday

获取一周中接下来n天的列表？

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