错误[IntrusionException] [安全失败匿名:null @ unknown-> / ExampleApplication / IntrusionException] INTRUSION-多种(2x)编码

时间:2018-06-29 12:57:18

标签: xss owasp esapi

我的项目中有以下代码行:

Comment

我收到以下错误:

  

错误[IntrusionException] [安全失败匿名:null @ unknown->   / ExampleApplication / IntrusionException]插入-多个(2x)   检测到的编码   http://www.google.co.jp/url?sa=t&rct=j&q=&esrc=s&source=web&cd=2&cad=rja&uact=8&ved=0ahUKEwjwscD6ifjbAhVOgK0KHT_DAYsQFggxMAE&url=http%3A%2F%2Fwww.nequipment.eu%2Fassets%2Fimported%2Ftransformations%2Fcontent%2Fproduct-details%2F%257Blanguage%257D_Brochure%2FC061657EB4C64903B6BEB38FBAC03445%2FDX140LC-3_AS8-3_EN.pdf&usg=AOvVaw2923Vp0vsPQHvZ7gDbPFGs   2018-06-29 00:29:31,559警告[com.xxxxx.framework.utils.XSSUtil]   参数值无效,设置为空。值:   http://www.google.co.jp/url?sa=t&rct=j&q=&esrc=s&source=web&cd=2&cad=rja&uact=8&ved=0ahUKEwjwscD6ifjbAhVOgK0KHT_DAYsQFggxMAE&url=http%3A%2F%2Fwww.nequipment.eu%2Fassets%2Fimported%2Ftransformations%2Fcontent%2Fproduct-details%2F%257Blanguage%257D_Brochure%2FC061657EB4C64903B6BEB38FBAC03445%2F140LC-3_X160LC-3_EN.pdf&usg=AOvVaw2923Vp0vsPQHvZ7gDbPFGs   org.owasp.esapi.errors.IntrusionException:输入验证失败     在   org.owasp.esapi.reference.DefaultEncoder.canonicalize(DefaultEncoder.java:181)     在   org.owasp.esapi.reference.DefaultEncoder.canonicalize(DefaultEncoder.java:122)

警告是什么意思,我该如何消除?

0 个答案:

没有答案