代码
library(igraph)
g <- graph.tree(n = 2 ^ 3 - 1, children = 2)
node_labels <- c("", "Group A", "Group B", "(1)Text", "(2)I am a longer text", "(3)I am a long long long text", "(4)X")
lay = layout.reingold.tilford(g)
plot(g,
vertex.size = 4, # node size
vertex.color = '#C4D8E2', # node color
vertex.label = node_labels, # node labels
vertex.label.dist = 5, # node label size
vertex.label.font = 2, # node label type (bold)
vertex.label.degree=0.0,
margin=c(0,0,0,0),
layout=-lay[, 2:1]
)
给我一个带有标签的图。如何对齐标签1 .. 4,使它们左对齐,在圆旁边,而不是居中对齐?从我的角度来看,第3条是正确的。切换到ggraph是一种选择,但是在这里旋转标签无效。
答案 0 :(得分:0)
如果您可以手动更改每个标签的距离,如下所示-
plot(g,
vertex.size = 4,
vertex.color = '#C4D8E2',
vertex.label = node_labels,
vertex.label.dist = c(0,0,0,0,8,12,0), # vector of distance
vertex.label.font = 2,
vertex.label.degree=0.0,
margin=c(0,0,0,0),
layout=-lay[, 2:1]
)
或者您可能想要创建一个函数来从每个顶点获取这些长度。这是我留给您即兴创作的。
t1 <- sapply(node_labels, FUN = nchar)
t2 <- (t1 - min(t1))/ (max(t1) - min(t1))
t2 <- t2*12
plot(g,
vertex.size = 4,
vertex.color = '#C4D8E2',
vertex.label = node_labels,
vertex.label.dist = t2, # vector of distance
vertex.label.font = 2,
vertex.label.degree=0.0,
margin=c(0,0,0,0),
layout=-lay[, 2:1]
)
答案 1 :(得分:0)
下面是带有计算的代码:
library(igraph)
g <- graph.tree(n = 2 ^ 3 - 1, children = 2)
node_labels <- c("", "Group A", "Group B", "(1)Text", "(2)I am a longer text", "(3)I am a long long long text", "(4)X")
lay = layout.reingold.tilford(g)
t1 <- sapply(as.vector( node_labels), FUN = strwidth,units='in')
t2 <- (t1 - min(t1))/ (max(t1) - min(t1))*3+0.9
plot(g,
vertex.size = 4, # node size
vertex.color = '#C4D8E2', # node color
vertex.label = node_labels, # node labels
vertex.label.dist = t2, # node label size
vertex.label.font = 2, # node label type (bold)
vertex.label.degree=0.0,
margin=c(0,0,0,0),
layout=-lay[, 2:1]
)
这是一个更好的选择,但我做不到完美。