我有一个事件预订系统,其中显示了测试系统的可用插槽,我确实陷入了某种逻辑。
event_information
(A)存储有关事件的详细信息
event_machine_time
(B)存储测试笔记本电脑的事件时间,因为该机器仅在每天的特定时间被允许使用
*********************************************
* id * machine_name * start_time * end_time *
*********************************************
* 1 * LPN832 * 09:30:00 * 11:00:00 *
* 2 * LPN832 * 11:30:00 * 13:00:00 *
* 3 * LPN832 * 13:30:00 * 15:00:00 *
* 4 * MHY348 * 09:30:00 * 11:00:00 *
* 5 * MHY348 * 11:30:00 * 13:00:00 *
* 6 * MHY348 * 13:30:00 * 15:00:00 *
*********************************************
event_booking
(C)存储预订详细信息,包括该人是否通过c_confirmed
拒绝了该事件以及该人是否已经通过live
删除了
***************************************************************************
* id * information_id * candidate_id * machine_name_id * live * confirmed *
* 3 * 2666 * 356 * 1 * 1 * 2 *
* 4 * 2666 * 456 * 1 * 1 * 0 *
***************************************************************************
So my statuses for confirmed are:
0 - Not confirmed
1 - Confirmed
2 - Declined
My statuses for live are:
1 - Live
0 - Deleted
这是我的代码:
$Machine_Query = "SELECT *,
B.id AS m_id,
C.id AS c_id,
C.confirmed AS c_confirmed,
C.live AS c_live
FROM event_information A
INNER JOIN event_machine_time B on (1=1)
LEFT JOIN event_booking C on (B.id = C.machine_time_id and A.id = C.information_id )
WHERE A.id = '$Event_Data_ID'
ORDER BY B.machine_name ASC, B.start_time ASC";
$Machine = $dbconn->query($Machine_Query);
对于我的下拉选择器,我使用以下内容:
<?php foreach ($Machine->fetchAll() as $Machine_Row) {
//if($Machine_Row["confirmed"] == 2) { } else {
?>
<option value="<?php echo $Machine_Row["m_id"]; ?>" <?php if($Machine_Row["c_id"] != NULL && $Machine_Row["c_confirmed"] != "2" && $Machine_Row["c_live"] != "0") { echo "disabled"; } ?>><?php echo $Machine_Row["machine_name"]." - ".date("g:ia", strtotime($Machine_Row["start_time"])); ?><?php if($Machine_Row["c_id"] != NULL && $Machine_Row["c_confirmed"] != "2" && $Machine_Row["c_live"] != "0") { echo " - Booked"; } ?></option>
<?php } //} ?>
使用上面的示例显示输出,其中一个用户正在等待确认(因此它显示已预订),而另一个用户则拒绝了-请查看随后如何显示一个额外的广告位,并且如果我更改实时状态,则同样适用:
现在您可以看到我添加了一个已解决问题的修正程序,但是它确实应该存在于SQL中,因为如果不尝试隔离SQL程序就无法正确构建有效性检查器
这让我发疯了,很可能是我从它的角度看,所以非常感谢新鲜的眼睛。
答案 0 :(得分:0)
您可以选择一个布尔值来知道何时禁用该选项(此处为booked
):
(c.id IS NOT NULL AND C.confirmed != 2 AND C.live != 0) AS booked
我对您的PDO查询进行了一些编辑:
$Machine = $dbconn->prepare(
'SELECT
*,
B.id AS m_id,
C.id AS c_id,
C.confirmed AS c_confirmed,
C.live AS c_live,
(c.id IS NOT NULL AND C.confirmed != 2 AND C.live != 0) AS booked
FROM event_information A
INNER JOIN event_machine_time B
ON (1 = 1)
LEFT JOIN event_booking C
ON (B.id = C.machine_time_id AND A.id = C.information_id)
WHERE A.id = :event_data_id
ORDER BY B.machine_name ASC, B.start_time ASC'
);
$dbconn->execute([ 'event_data_id' => $Event_Data_ID ]);
这在HTML中输出要短得多(使用三元运算符在一行中看起来会更好):
<?php
foreach ($Machine->fetchAll() as $Machine_Row) {
?>
<option value="<?php echo $Machine_Row["m_id"]; ?>" <?php echo $Machine_Row['booked'] ? 'disabled' : ''; ?>>
<?php echo $Machine_Row["machine_name"] . " - " . date("g:ia", strtotime($Machine_Row["start_time"])) . ($Machine_Row['booked'] ? ' - Booked' : ''); ?>
</option>
<?php
}
?>