Question

var timer = setInterval(function () {
    if (myParam == 'what-i-need') {
        clearInterval(timer);
    }
}, 200);

当我进入时，我需要帮助弄清楚为什么：

movieDict = {"Munich":[2005, "Steven Spielberg"],
                        "The Prestige": [2006, "Christopher Nolan"],
                        "The Departed": [2006, "Martin Scorsese"],
                        "Into the Wild": [2007, "Sean Penn"],
                        "The Dark Knight": [2008, "Christopher Nolan"],
                        "Mary and Max": [2009, "Adam Elliot"],
                        "The King\'s Speech": [2010, "Tom Hooper"],
                        "The Artist": [2011, "Michel Hazanavicius"],
                        "The Help": [2011, "Tate Taylor"],
                        "Argo": [2012, "Ben Affleck"],
                        "12 Years a Slave": [2013, "Steve McQueen"],
                        "Birdman": [2014, "Alejandro G. Inarritu"],
                        "Spotlight": [2015, "Tom McCarthy"],
                        "The BFG": [2016, "Steven Spielberg"]}
promptForYear = True
while promptForYear:
    yearChoice = int(input("Enter a year between 2005 and 2016:\n"))
    if yearChoice<2005 or yearChoice>2016:
        print("N/A")   
    else:
        for key, value in movieDict.items():
            if value[0] == yearChoice:
                print(key + ", " + str(value[1]) )
        promptForYear = False          
menu = "MENU" \
        "\nSort by:" \
        "\ny - Year" \
        "\nd - Director" \
        "\nt - Movie title" \
        "\nq - Quit\n"
promptUser = True
first_time = True
while promptUser:
    if first_time == True:
        print()
        first_time = False
    print(menu)
    userChoice = input("Choose an option:\n")
    if userChoice == "q":
        promptUser = False
    elif userChoice=="y":
        year_sorted = {}            
        for key, value in sorted(movieDict.items(), key=lambda item: (item[1], item[0])):
            year = value[0]
            title = key
            director = value[1]
            if year not in year_sorted:
                year_sorted[year] = [[title, director]]
            else:
                year_sorted[year].append([title, director])            
        for year in sorted(year_sorted):
            print (year,end=':\n')
            movies = year_sorted[year]
            for movie in sorted(movies, key = lambda x:x[0]):
                print("\t"+movie[0] + ", " + movie[1])
            print()
    elif userChoice == "d":
        director_sorted = {}
        for key, value in sorted(movieDict.items(), key=lambda item: (item[1][1])):
            year = value[0]
            title = key
            director = value[1]
            if director not in director_sorted:
                director_sorted[director] = [[title, year]]
            else:
                director_sorted[director].append([title, year])            
        for director in sorted(director_sorted):
            print (director,end=':\n')
            movies = director_sorted[director]
            for movie in sorted(movies, key = lambda x:x[0]):
                print("\t"+movie[0] + ", " + str(movie[1]))            
            print()
    elif userChoice == "t":
        for key, value in sorted(movieDict.items(), key=lambda item: (item[0], item[1])):
            print(key,end=':\n')
            print("\t" + str(value[1]) + ", " + str(value[0])+"\n")
    else:
        print("Invalid input")

2006年，电影的排序如下：

2014
y
q

但是我需要它们打印出来像：

2006:
    The Departed, Martin Scorsese
    The Prestige, Christopher Nolan

当我进入时：

2006:
    The Prestige, Christopher Nolan
    The Departed, Martin Scorsese

打印：

2008
d
q

但我需要打印：

Christopher Nolan:
    The Dark Knight, 2008
    The Prestige, 2006

非常感谢任何帮助，谢谢！

Answer 1

此代码段：

movies = year_sorted[year]
for movie in sorted(movies, key = lambda x:x[0]):
  print("\t"+movie[0] + ", " + movie[1])

强制你的年份排序按原样排出。你告诉它按字母顺序对电影进行分类，这正是它正在做的事情。当你按导演排序时，你会发生同样的事情。因此，如果您希望您的电影与其相反，那么您需要告诉它这样做

movies = year_sorted[year]
for movie in sorted(movies, key = lambda x:x[0], reverse=True):
  print("\t"+movie[0] + ", " + movie[1])

您可能还打算按导演/年而不是标题排序，在这种情况下，您需要将lambda更改为lambda x:x[1]，以便按列表中的第二个对象而不是第一个对象进行排序。

我需要这个代码我有一个我无法弄清楚的排序问题

1 个答案: