Question

我是sql的新手并且正在努力解决这个非常简单的任务。

考虑，

    with table1 as (select '1' col1 from dual union
select '2' col1 from dual union
select 'NO_PATTERN' col1 from dual union
select 'RANDOM_STUFF' col1 from dual)
    select * from table1;

和

    with table2 as (select 'aaa' col2 from dual union
select '4' col2 from dual union
select 'qwewqeq' col2  from dual
union select 'UUUUUU' col2 from dual)
    select * from table2;

我想在两列之间执行cbind()到一个新表中，这是table1。[col1]和table2 [col2]的“垂直联合”。

预期解决方案是：

    with solution as (select '1' col1, 'aaa' col2 from dual union
select '2' col1, '4' col2 from dual union
select 'NO_PATTERN'  col1, 'qwewqeq' col2 from dual union
select 'RANDOM_STUFF'  col1, 'UUUUUU'  col2 from dual)
    select * from solution;

有什么想法吗？

Answer 1

在Oracle中，您需要明确定义一些值以获取有序数据;没有它，每次运行查询时都可能有不同的结果。

根据您的数据：

WITH table1 AS
         (SELECT 1 rn, '1'            col1 FROM DUAL UNION
          SELECT 2 rn, '2'            col1 FROM DUAL UNION
          SELECT 3 rn, 'NO_PATTERN'   col1 FROM DUAL UNION
          SELECT 4 rn, 'RANDOM_STUFF' col1 FROM DUAL),
     table2 AS
         (SELECT 1 rn, 'aaa'     col2 FROM DUAL UNION
          SELECT 2 rn, '4'       col2 FROM DUAL UNION
          SELECT 3 rn, 'qwewqeq' col2 FROM DUAL UNION
          SELECT 4 rn, 'UUUUUU'  col2 FROM DUAL)
SELECT col1, col2, t1.rn
from (select  row_number() over (order by rn) as rn, col1 from table1 ) t1
       inner join 
     (select row_number() over (order by rn) as rn, col2 from table2 ) t2
     on (t1.rn = t2.rn)

给出：

COL1         COL2            RN
------------ ------- ----------
1            aaa              1
2            4                2
NO_PATTERN   qwewqeq          3
RANDOM_STUFF UUUUUU           4

没有明确的排序，例如，

WITH table1 AS
         (SELECT '1'            col1 FROM DUAL UNION
          SELECT '2'            col1 FROM DUAL UNION
          SELECT 'NO_PATTERN'   col1 FROM DUAL UNION
          SELECT 'RANDOM_STUFF' col1 FROM DUAL),
     table2 AS
         (SELECT 'aaa'     col2 FROM DUAL UNION
          SELECT '4'       col2 FROM DUAL UNION
          SELECT 'qwewqeq' col2 FROM DUAL UNION
          SELECT 'UUUUUU'  col2 FROM DUAL)
SELECT col1, col2, t1.rn
from (select  rownum as rn, col1 from table1 ) t1
       inner join 
     (select rownum as rn, col2 from table2 ) t2
     on (t1.rn = t2.rn)

给出

COL1         COL2            RN
------------ ------- ----------
1            4                1
2            UUUUUU           2
NO_PATTERN   aaa              3
RANDOM_STUFF qwewqeq          4

Answer 2

如果您不想订购它们，这将是一种简单的方法-

select *, ROW_NUMBER() OVER (ORDER BY (SELECT 100)) AS SNO into #0 FROM Table 2

select *, ROW_NUMBER() OVER (ORDER BY (SELECT 100)) AS SNO into #1 FROM Table1

select a.*, b.* into #3 from #0 a join #1 b on a.SNO = b.SNO

从这里得到想法-

https://blog.sqlauthority.com/2015/05/05/sql-server-generating-row-number-without-ordering-any-columns/

相当于Oracle中的R cbind（）函数？

2 个答案: