我已经设置了一对多的关系,并希望在删除父级时删除子级。
我忘记这样做了,当因为孩子存在而拒绝删除父母时,这在MySQL的制作中造成了一个错误。
我想编写一个功能测试,但SQLite默认禁用外键检查。
如何在控制器使用的连接上PRAGMA foreign_keys = ON
?我在测试端(灯具)上运行了这个,但这不是相同的连接,因此仍然禁用外键检查,并且删除具有现有子节点的父节点不会失败(它应该)。
答案 0 :(得分:0)
覆盖捆绑包的boot
功能,并在那里执行请求:
public function boot() {
parent::boot();
$env = $this->container->getParameter('kernel.environment');
if ($env !== "test") {
return;
}
/** @var Connection $connection */
$connection = $this->container->get('doctrine')->getConnection();
// Get initial state -- should be disabled
$statement = $connection->prepare("PRAGMA foreign_keys");
$statement->execute();
echo __FILE__ . "@" . __LINE__ . "\n";
print_r($statement->fetchAll());
// Actually enable the foreign key checks on this connection
$connection->exec("PRAGMA foreign_keys = ON;");
// See if it was enabled
$statement = $connection->prepare("PRAGMA foreign_keys");
$statement->execute();
echo __FILE__ . "@" . __LINE__ . "\n";
print_r($statement->fetchAll());
}
这会产生以下结果:
./src/AppBundle/DependencyInjection/Compiler/DoctrineCompilerPass.php@23
Array
(
[0] => Array
(
[foreign_keys] => 0
)
)
./src/AppBundle/DependencyInjection/Compiler/DoctrineCompilerPass.php@30
Array
(
[0] => Array
(
[foreign_keys] => 1
)
)
现在,根据您使用的灯具,您可能需要在擦除数据库架构时禁用外键检查:
public function setUp() {
$manager = $this->getContainer()
->get('doctrine')
->getManager();
if (!isset($metadata)) {
$metadata = $manager->getMetadataFactory()
->getAllMetadata();
}
$schemaTool = new SchemaTool($manager);
// Disable the foreign key checks before the database is wiped
$manager->getConnection()->exec("PRAGMA foreign_keys = OFF");
$schemaTool->dropDatabase();
if (!empty($metadata)) {
$schemaTool->createSchema($metadata);
}
// Re-enable the foreign key checks now that it is created
$manager->getConnection()->exec("PRAGMA foreign_keys = ON");
$this->postFixtureSetup();
$this->referenceRepository = $this->loadFixtures(array(ZZZ::class))->getReferenceRepository();
$this->loadFixtures(array(ZZZ::class));
$this->client = $this->makeClient();
}