我正在尝试在Java(PC)和Android之间进行Socket程序。 APP从图库中选择图像并显示我选择的图像。当我运行程序时,我发生了这个错误。我检查了关于FİleNotFOundException的其他帖子,但我找不到任何解决方案。任何人都可以帮助我吗?
这是我的代码
public class SendfileActivity extends Activity {
/** Called when the activity is first created. */
private static final int SELECT_PICTURE = 1;
private String selectedImagePath;
private String yol;
private ImageView img;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
System.out.println("34");
img = (ImageView) findViewById(R.id.ivPic);
System.out.println("36");
((Button) findViewById(R.id.bBrowse))
.setOnClickListener(new OnClickListener() {
public void onClick(View arg0) {
System.out.println("40");
Intent intent = new Intent();
intent.setType("image/*");
intent.setAction(Intent.ACTION_GET_CONTENT);
startActivityForResult(
Intent.createChooser(intent, "Select Picture"),
SELECT_PICTURE);
System.out.println("47");
}
});
;
System.out.println("51");
Button send = (Button) findViewById(R.id.bSend);
final TextView status = (TextView) findViewById(R.id.tvStatus);
send.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View arg0) {
new Thread(new SocketThread()).start();
}
});
}
public void onActivityResult(int requestCode, int resultCode, Intent data) {
if (resultCode == RESULT_OK) {
if (requestCode == SELECT_PICTURE) {
Uri selectedImageUri = data.getData();
yol = selectedImageUri.getPath();
selectedImagePath = getPath(selectedImageUri);
TextView path = (TextView) findViewById(R.id.tvPath);
path.setText("Image Path : " + yol);
img.setImageURI(selectedImageUri);
}
}
}
public String getPath(Uri uri) {
String[] projection = { MediaStore.Images.Media.DATA };
Cursor cursor = managedQuery(uri, projection, null, null, null);
int column_index = cursor
.getColumnIndex(MediaStore.Images.Media.DATA);
cursor.moveToFirst();
return cursor.getString(column_index);
}
class SocketThread implements Runnable {
@Override
public void run() {
Socket sock;
try {
sock = new Socket("10.0.2.2", 8080);
System.out.println("Connecting...");
// sendfile
File myFile = new File(yol);
byte[] mybytearray = new byte[(int) myFile.length()];
FileInputStream fis = null;
try {
fis = new FileInputStream(myFile);
} catch (FileNotFoundException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
BufferedInputStream bis = new BufferedInputStream(fis);
bis.read(mybytearray, 0, mybytearray.length);
OutputStream os = sock.getOutputStream();
System.out.println("Sending...");
os.write(mybytearray, 0, mybytearray.length);
os.flush();
sock.close();
} catch (UnknownHostException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
}
这是我的logcat。
W/System.err: java.io.FileNotFoundException: /document/image:78 (No such file or directory)
W/System.err: at java.io.FileInputStream.open(Native Method)
at java.io.FileInputStream.<init>(FileInputStream.java:146)
at com.example.murat.dhoproje.SendfileActivity$SocketThread.run(SendfileActivity.java:115)
at java.lang.Thread.run(Thread.java:761)
答案 0 :(得分:0)
java.io.FileNotFoundException:/ document / image:78
这是
获得的不可能的非现有文件系统路径yol = selectedImageUri.getPath();
但是你必须完全不同并使用InputStream而不是FileInputStream。所以改变
FileInputStream fis = null; 尝试{ fis = new FileInputStream(myFile);
到
InputStream is = getContentResolver().openInputStream(data.getData());
使用is
fis
对<?php
if(isset($_GET['code'])) $acode = $_GET['code'];
else die("No code!");
$con=mysqli_connect("xxx","xxx","xxx","xxx");
// Check connection
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
} else {
$acode = mysqli_real_escape_string($con, $acode);
$query = mysqli_query($con,"select * from login where activation_code='$acode'")
or die(mysqli_error($con));
if(mysqli_num_rows($query) == 0) {
echo "Wrong code";
die();
} elseif (mysqli_num_rows ($query)==1 && isset($_POST['pass'])) {
$pass = mysqli_real_escape_string($con, $_POST['pass']);
$query3 = mysqli_query($con,"update login set Password='$pass' where activation_code='$acode'")
or die(mysqli_error($con));
echo 'Password Changed';
}
}
?>
enter code here
<form action="resetpass.php?code=<?php echo $_GET['code'];?>" method="POST">
<p>New Password:</p><input type="password" name="pass" />
<input type="submit" name="submit" value="Signup!" />
</form>
做了什么。
顺便说一下:与socket编程没什么关系。您可能已经尝试在onActivityResult()中打开该文件,以向您和我们展示问题。