Question

我正在尝试在我的JavaFX应用程序中返回IP地址但是我不确定我做得对。我在java中有点生疏（自从我上次为任何大学申请等写了两年以来）。有人能够在尝试将返回的主机地址放入文本字段方面告诉我哪里出错了。区域以**

突出显示

import java.net.InetAddress;
import javafx.application.Application;
import javafx.geometry.Insets;
import javafx.scene.Scene;
import javafx.scene.control.Button;
import javafx.scene.control.Label;
import javafx.scene.control.TextField;
import javafx.scene.layout.GridPane;
import javafx.stage.Stage;

public class Main extends Application {
    Stage window;

    public static void main(String[] args) {
        launch(args);
    }

    @Override
    public void start(Stage primaryStage) throws Exception {
        window = primaryStage;
        window.setTitle("thenewboston - JavaFX");

        //GridPane with 10px padding around edge
        GridPane grid = new GridPane();
        grid.setPadding(new Insets(10, 10, 10, 10));
        grid.setVgap(8);
        grid.setHgap(10);

        //Name Label - constrains use (child, column, row)
        Label nameLabel = new Label("Find my IP Address:");
        nameLabel.setId("bold-label");
        GridPane.setConstraints(nameLabel, 0, 0);

        //Search IP Address 
        Button IPlookupButton =new Button("Search for IP");
        GridPane.setConstraints(IPlookupButton, 1, 0);
        IPlookupButton.setOnAction(event -> {
            try {
                InetAddress thisIp = InetAddress.getLocalHost();
                System.out.println("IP:" + thisIp.getHostAddress());
            } catch (Exception e) {
                e.printStackTrace();
            }
        });

        **//Name Input
        TextField nameInput = new Textfield(thisIp.getHostAddress());
        GridPane.setConstraints(nameInput, 3, 0);**

        //Password Label
        Label passLabel = new Label("MAC Address Look UP:");
        GridPane.setConstraints(passLabel, 0, 1);

        //Password Input
        TextField passInput = new TextField();
        passInput.setPromptText("password");
        GridPane.setConstraints(passInput, 1, 1);

        //Login
        Button loginButton = new Button("Log In");
        GridPane.setConstraints(loginButton, 1, 2);

        //Sign up
        Button signUpButton = new Button("Sign Up");
        signUpButton.getStyleClass().add("button-blue");
        GridPane.setConstraints(signUpButton, 1, 3);

        //Add everything to grid
        grid.getChildren().addAll(nameLabel, IPlookupButton, nameInput, 
        passLabel, passInput, loginButton, signUpButton);

        Scene scene = new Scene(grid, 600, 600);
        scene.getStylesheets().add("colour.css");
        window.setScene(scene);
        window.show();

    }

}

Answer 1

只需在按钮的处理程序中设置文本字段的文本：

#include <stdio.h>
#include <stdlib.h>
int main (){
    int n ;
    int arr1[n];
    long long int arrcount ;
    scanf("%d" , n);
    for(int i = 0; i <= n; i++) {
        scanf("%d" , &arr1[n]);
    }
    for( int i = 0; i <=n; i++) {
        arrcount = arrcount + arr1[n];
    }
    printf("%li" , arrcount);
}

TextField中的返回值

1 个答案: