我正在编写一个bash脚本，它在AWS中执行许多常用功能。
当我运行脚本时，我试图调用的函数没有运行，脚本以“你在AWS中的工作完成”的消息结束：
These are the AWS Accounts:
1 Lab
2 Billing
Please enter a number for the account you want to work in.
Account Number:
1
These are the actions possible in AWS:
1 Add User and Access Keys
2 Delete Snapshots
Enter an action in AWS:
1
Your work in AWS is done.
Your work in AWS is done.
我的脚本中的两个函数为脚本的其余部分奠定了基础：
choose_account设置您将使用的AWS账户.select_action设置一个名为user_action的变量，该变量包含函数的名称。
但是当我尝试在脚本末尾的if / else语句中调用该函数时，不会调用任何函数，脚本以“您的工作在AWS中完成”结束。
这是我的剧本：
#!/usr/bin/env bash
PATH=/home/myuser/.local/bin:$PATH
choose_account(){
echo "These are the KPMG AWS Accounts:"
echo "1 Lab"
echo "2 Billing"
echo
echo "Please enter a number for the account you want to work in."
echo "Account Number: "
read -r aws_account_number
if [ "$aws_account_number" -eq 1 ]; then
declare -i accountnumber=423214542344
return
elif [ "$aws_account_number" -eq 2 ]; then
declare -i accountnumber=188523423411
return
else
echo "Unkown account"
fi
echo
echo
}
choose_action(){
echo "These are the actions possible in AWS: "
echo "1 Add User and Access Keys"
echo "2 Delete Snapshots"
echo "Enter an action in AWS: "
read -r action
echo
echo
if [ "$action" -eq "1" ]; then
user_action=add_user
aws_file="source_files/aws_environments_nonprod.txt"
return
elif [ "$action" = ="2" ]; then
user_action=add_user
aws_file="source_files/aws_snapshots_prod.tx"
return
else
echo "Action Not Chosen"
fi
}
add_user(){
aws_user="us-svc-food"
aws_group1="grp-read-only"
aws_group2="grp-food-read-only"
IFS=$'\n'
set -f
for i in $aws_file
do
echo "adding user: $aws_user to account: $i"
aws iam create-user --user-name $aws_user --output=json --profile="$i"
echo
sleep 5
echo "add user: $aws_user to group: $aws_group1"
aws iam add-user-to-group --user-name $aws_user --group-name $aws_group1 --output=json --profile="$i"
sleep 5
echo "add user: $aws_user to group: $aws_group2"
aws iam add-user-to-group --user-name $aws_user --group-name $aws_group2 --output=json --profile="$i"
sleep 5
echo
echo "verify the user $aws_user is there in: $i"
aws iam get-user --user-name $aws_user --output=json --profile="$i"
sleep 5
echo
echo "*************************************************"
echo "creating the access key for $aws_user to account: $i"
aws iam create-access-key --user-name $aws_user --output=json --profile="$i"
echo "**************************************************"
sleep 30
echo
echo "verify the user access keys for $aws_user on account: $i"
aws iam list-access-keys --user-name $aws_user --output=json --profile="$i"
echo
echo "***************************************************"
echo
sleep 5
done
set +f
unset IFS
}
delete_snapshots(){
IFS=$'\n'
set -f
for i in $aws_file
do
echo "*****************************************************************"
echo "Deleting snapshot: $i:"
aws ec2 delete-snapshot --snapshot-id="$i" --profile="$aws_key" 2>&1 | sed -e 's/^An error occurred.*when calling the DeleteSnapshot operation: //'
echo "*****************************************************************"
echo; echo; echo; echo; echo
sleep 5
echo "*****************************************************************"
echo "Verify that snapshot: $i is gone:"
aws ec2 describe-snapshots --snapshot-ids="$i" --profile="$aws_key" 2>&1 | sed -e 's/^An error occurred.*when calling the DescribeSnapshots operation: //g'
echo "*****************************************************************"
echo; echo; echo; echo; echo
done
set +f
unset IFS
}
choose_account
choose_action
declare -a arr=("423214542344" "188523423411")
for i in "${arr[@]}"
do
if [ "$accountnumber" == 423214542344 ]; then
aws_account="AWS Lab"
aws_key="kpmg-lab"
echo "$user_action in account: $aws_account"
"$user_action"
return
elif [ "$accountnumber" == 188523423411 ]; then
aws_account="AWS Billing"
aws_key="kpmg-bill"
echo "$user_action in account: $aws_account"
"$user_action"
return
else
echo "Your work in AWS is done."
fi
done
我希望$ user_action是一个函数调用。
编辑：
我创造了一些详细的输出。
PS4=':$BASH_SOURCE:$LINENO+' bash -x aws_tools_test.sh
:aws_tools_test.sh:3+PATH=/home/myuser/.local/bin:/home/myuser/bin:/home/myuser/.local/bin:/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games:/usr/local/games:/snap/bin
:aws_tools_test.sh:113+choose_account
:aws_tools_test.sh:7+echo 'These are the KPMG AWS Accounts:'
These are the KPMG AWS Accounts:
:aws_tools_test.sh:8+echo '1 Lab'
1 Lab
:aws_tools_test.sh:9+echo '2 Billing'
2 Billing
:aws_tools_test.sh:10+echo
:aws_tools_test.sh:11+echo 'Please enter a number for the account you want to work in.'
Please enter a number for the account you want to work in.
:aws_tools_test.sh:12+echo 'Account Number: '
Account Number:
:aws_tools_test.sh:13+read -r aws_account_number
1
:aws_tools_test.sh:15+'[' 1 -eq 1 ']'
:aws_tools_test.sh:16+declare -i accountnumber=423214542344
:aws_tools_test.sh:17+return
:aws_tools_test.sh:114+choose_action
:aws_tools_test.sh:31+echo 'These are the actions possible in AWS: '
These are the actions possible in AWS:
:aws_tools_test.sh:32+echo '1 Add User and Access Keys'
1 Add User and Access Keys
:aws_tools_test.sh:33+echo '2 Delete Snapshots'
2 Delete Snapshots
:aws_tools_test.sh:34+echo 'Enter an action in AWS: '
Enter an action in AWS:
:aws_tools_test.sh:35+read -r action
1
:aws_tools_test.sh:36+echo
:aws_tools_test.sh:37+echo
:aws_tools_test.sh:38+'[' 1 -eq 1 ']'
:aws_tools_test.sh:39+user_action=add_user
:aws_tools_test.sh:40+aws_file=source_files/aws_environments_nonprod.txt
:aws_tools_test.sh:41+return
:aws_tools_test.sh:116+arr=("423214542344" "188523423411")
:aws_tools_test.sh:116+declare -a arr
:aws_tools_test.sh:117+for i in '"${arr[@]}"'
:aws_tools_test.sh:119+'[' '' == 423214542344 ']'
:aws_tools_test.sh:125+'[' '' == 188523423411 ']'
:aws_tools_test.sh:132+echo 'Your work in AWS is done.'
Your work in AWS is done.
:aws_tools_test.sh:117+for i in '"${arr[@]}"'
:aws_tools_test.sh:119+'[' '' == 423214542344 ']'
:aws_tools_test.sh:125+'[' '' == 188523423411 ']'
:aws_tools_test.sh:132+echo 'Your work in AWS is done.'
Your work in AWS is done.
看起来$ accountnumber变量未设置。所以函数没有被调用。那是为什么？
答案 0 :(得分：1)
在函数中使用时，declare内置使变量本地化为该函数。因此，当您在accountnumber中声明choose_account时，该值在脚本的顶层不可见。
看起来确实需要声明此变量的类型，因此declare -i是不必要的。只做一个普通的变量赋值。如果你真的觉得需要将它作为整数变量，请将声明放在顶级脚本而不是函数中，然后在函数中分配它。或者完全避免访问全局变量，并让函数回显结果：
declare -i accountnumber=$(choose_account)