Question

我有一个带有一些重复数据的oracle视图我正试图从我的视图中删除那些重复的行：

这是我的观看代码：

 CREATE OR REPLACE FORCE VIEW "GLSID"."VW_GLSID_DOCUMENTS" ("ID", "PARENT_ID", "DOCUMENT_TYPE_ID", "AMOUNT") AS 
  SELECT  container.id,
   container.container_id AS parent_id,
   document.document_type_id,
   container.number_of_documents AS amount
   FROM container
   JOIN document ON document.container_id = container.id ;

此视图为我提供了以下结果：

ID | PARENT_ID | DOCUMENT_TYPE_ID | Amount
21      23          3                2
21      23          3                2
21      23          3                1
15      26          3                4

有人可以帮助我从这个视图中删除重复的行来获取这个：

ID | PARENT_ID | DOCUMENT_TYPE_ID | Amount
21      23          3                2
21      23          3                1
15      26          3                4

提前致谢

Answer 1

返回结果后，最简单的方法是在SELECT中使用DISTINCT：

 CREATE OR REPLACE FORCE VIEW "GLSID"."VW_GLSID_DOCUMENTS" ("ID", "PARENT_ID", "DOCUMENT_TYPE_ID", "AMOUNT") AS 
  SELECT DISTINCT container.id,
   container.container_id AS parent_id,
   document.document_type_id,
   container.number_of_documents AS amount
   FROM container
   JOIN document ON document.container_id = container.id ;

如果您发现文档计数错误，可以尝试这样做：

 CREATE OR REPLACE FORCE VIEW "GLSID"."VW_GLSID_DOCUMENTS" ("ID", "PARENT_ID", "DOCUMENT_TYPE_ID", "AMOUNT") AS 
  SELECT container.id,
         container.container_id AS parent_id,
         document.document_type_id,
         SUM(container.number_of_documents) AS amount
   FROM container
   JOIN document ON document.container_id = container.id 
   GROUP BY container.id,
            container.container_id,
            document.document_type_id

Answer 2

也许您应该使用 DISTINCT 运算符

CREATE OR REPLACE FORCE VIEW "GLSID"."VW_GLSID_DOCUMENTS" ("ID", "PARENT_ID", "DOCUMENT_TYPE_ID", "AMOUNT") AS 
SELECT DISTINCT container.id,
container.container_id AS parent_id,
document.document_type_id,
container.number_of_documents AS amount
FROM container
JOIN document ON document.container_id = container.id ;

从视图oracle中删除重复的行

2 个答案: