Question

我有两个带到表的模型，例如：

class A(models.Model):
    title = models.CharField(max_length=500)
    bs = models.ManyToManyField(to='app.B', through='app.AB', blank=True)

    content_panels = [
        FieldPanel('title'),
        FieldPanel('fields'),    # what should go here?
    ]

class AB(models.Model):
    a = models.ForeignKey(to='app.A')
    b = models.ForeignKey(to='app.B')
    position = models.IntegerField()

    class Meta:
        unique_together = ['a', 'b']

我在尝试保存时遇到以下错误：

无法在指定中间模型的ManyToManyField上设置值。

这个错误对我有意义。我应该保存AB实例。我不确定在Wagtail中实现这一目标的最佳途径是什么。

Answer 1

您需要的是InlinePanel：http://docs.wagtail.io/en/v2.0.1/getting_started/tutorial.html#images

from wagtail.admin.edit_handlers import FieldPanel, InlinePanel
from wagtail.core.models import Orderable
from modelcluster.fields import ParentalKey

# the parent object must inherit from ClusterableModel to allow parental keys;
# this happens automatically for Page models
from modelcluster.models import ClusterableModel

class A(ClusterableModel):
    title = models.CharField(max_length=500)

    content_panels = [
        FieldPanel('title'),
        InlinePanel('ab_objects'),
    ]

class AB(Orderable):
    a = ParentalKey('app.A', related_name='ab_objects')
    b = models.ForeignKey('app.B')
    panels = [
        FieldPanel('b'),
    ]

Django，Wagtail管理员：使用`through`处理多对多

1 个答案: